我正在抓取一个网页,当我得到一个结果时,除了我的卡名列之外,其他所有内容看起来都很好,因为我在卡名之前得到了\n
。如何防止输出?
# Scraping
def parse(self, response):
item = GameItem()
item["Category"] = response.css("span.titletext::text").extract()
for game in response.css("tr[class^=deckdbbody]"):
item["card_name"] = game.css("a.card_popup::text").extract_first()
if item["card_name"] != None:
saved_name = item["card_name"]
else:
item["card_name"] = saved_name
item["Condition"] = game.css("td[class^=deckdbbody].search_results_7 a::text").get()
item["stock"] = game.css("td[class^=deckdbbody].search_results_8::text").extract_first()
item["Price"] = game.css("td[class^=deckdbbody].search_results_9::text").extract_first()
yield item
样本输出
{"Category": ["Duel Decks: Venser vs. Koth"], "card_name": "\nAether Membrane", "Condition": "NM/M", "stock": "93", "Price": "$0.59"},
{"Category": ["Duel Decks: Venser vs. Koth"], "card_name": "\nAether Membrane", "Condition": "PL", "stock": "59", "Price": "$0.49"},
{"Category": ["Duel Decks: Venser vs. Koth"], "card_name": "\nAngelic Shield", "Condition": "NM/M", "stock": "35", "Price": "$0.25"},
{"Category": ["Duel Decks: Venser vs. Koth"], "card_name": "\nAnger", "Condition": "NM/M", "stock": "9", "Price": "$1.49"},
{"Category": ["Duel Decks: Venser vs. Koth"], "card_name": "\nAnger", "Condition": "PL", "stock": "49", "Price": "$1.19"},
答案 0 :(得分:4)
内置字符串方法strip()
(str.strip()
)删除所有可打印的字符。
答案 1 :(得分:1)
这应该做到。
# Scraping
def parse(self, response):
item = GameItem()
item["Category"] = response.css("span.titletext::text").extract()
for game in response.css("tr[class^=deckdbbody]"):
item["card_name"] = game.css("a.card_popup::text").extract_first()
# strip added here ->
if item["card_name"] != None:
saved_name = item["card_name"].strip()
else:
item["card_name"] = saved_name
item["Condition"] = game.css("td[class^=deckdbbody].search_results_7 a::text").get()
item["stock"] = game.css("td[class^=deckdbbody].search_results_8::text").extract_first()
item["Price"] = game.css("td[class^=deckdbbody].search_results_9::text").extract_first()
yield item
如果可能的话,一个不相关的代码简化技巧:
# Scraping
def parse(self, response):
item = GameItem()
# declare saved_name before hand to avoid NameError
saved_name = ""
item["Category"] = response.css("span.titletext::text").extract()
for game in response.css("tr[class^=deckdbbody]"):
# simplify conditional statement
saved_name = game.css("a.card_popup::text").extract_first() or saved_name
item["card_name"] = saved_name.strip()
item["Condition"] = game.css("td[class^=deckdbbody].search_results_7 a::text").get()
item["stock"] = game.css("td[class^=deckdbbody].search_results_8::text").extract_first()
item["Price"] = game.css("td[class^=deckdbbody].search_results_9::text").extract_first()
yield item