因此,我正在尝试构建一个函数,该函数返回某些客户端订阅中包含的项目的记录。
所以我一直在建立以下内容:
2种类型:
CREATE OR REPLACE TYPE PGM_ROW AS OBJECT
(
pID NUMBER(10),
pName VARCHAR2(300)
);
CREATE OR REPLACE TYPE PGM_TAB AS TABLE OF PGM_ROW;
1个功能:
CREATE OR REPLACE FUNCTION FLOGIN (USER_ID NUMBER) RETURN PGM_TAB
AS
SELECTED_PGM PGM_TAB;
BEGIN
FOR RESTRICTION
IN ( SELECT (SELECT LISTAGG (ID_CHANNEL, ',')
WITHIN GROUP (ORDER BY ID_CHANNEL)
FROM (SELECT DISTINCT CHA2.ID_CHANNEL
FROM CHANNELS_ACCESSES CHA2
JOIN CHANNELS CH2
ON CH2.ID = CHA2.ID_CHANNEL
WHERE CHA2.ID_ACCESS = CMPA.ID_ACCESS
AND CH2.ID_CHANNELS_GROUP = CG.ID))
AS channels,
(SELECT LISTAGG (ID_SUBGENRE, ',')
WITHIN GROUP (ORDER BY ID_SUBGENRE)
FROM (SELECT DISTINCT SGA2.ID_SUBGENRE
FROM SUBGENRES_ACCESSES SGA2
JOIN CHANNELS_ACCESSES CHA2
ON CHA2.ID_ACCESS = SGA2.ID_ACCESS
JOIN CHANNELS CH2
ON CH2.ID = CHA2.ID_CHANNEL
WHERE SGA2.ID_ACCESS = CMPA.ID_ACCESS
AND CH2.ID_CHANNELS_GROUP = CG.ID))
AS subgenres,
CG.NAME,
A.BEGIN_DATE,
A.END_DATE,
CMP.PREVIEW_ACCESS
FROM USERS U
JOIN COMPANIES_ACCESSES CMPA
ON U.ID_COMPANY = CMPA.ID_COMPANY
JOIN COMPANIES CMP ON CMP.ID = CMPA.ID_COMPANY
JOIN ACCESSES A ON A.ID = CMPA.ID_ACCESS
JOIN CHANNELS_ACCESSES CHA
ON CHA.ID_ACCESS = CMPA.ID_ACCESS
JOIN SUBGENRES_ACCESSES SGA
ON SGA.ID_ACCESS = CMPA.ID_ACCESS
JOIN CHANNELS CH ON CH.ID = CHA.ID_CHANNEL
JOIN CHANNELS_GROUPS CG ON CG.ID = CH.ID_CHANNELS_GROUP
WHERE U.ID = USER_ID
GROUP BY CG.NAME,
A.BEGIN_DATE,
A.END_DATE,
CMPA.ID_ACCESS,
CG.ID,
CMP.PREVIEW_ACCESS)
LOOP
SELECT PFT.ID_PROGRAM, PFT.LOCAL_TITLE
BULK COLLECT INTO SELECTED_PGM
FROM PROGRAMS_FT PFT
WHERE PFT.ID_CHANNEL IN
( SELECT TO_NUMBER (
REGEXP_SUBSTR (RESTRICTION.CHANNELS,
'[^,]+',
1,
ROWNUM))
FROM DUAL
CONNECT BY LEVEL <=
TO_NUMBER (
REGEXP_COUNT (RESTRICTION.CHANNELS,
'[^,]+')))
AND PFT.ID_SUBGENRE IN
( SELECT TO_NUMBER (
REGEXP_SUBSTR (RESTRICTION.SUBGENRES,
'[^,]+',
1,
ROWNUM))
FROM DUAL
CONNECT BY LEVEL <=
TO_NUMBER (
REGEXP_COUNT (RESTRICTION.SUBGENRES,
'[^,]+')))
AND (PFT.LAUNCH_DATE BETWEEN RESTRICTION.BEGIN_DATE
AND RESTRICTION.END_DATE);
END LOOP;
RETURN SELECTED_PGM;
END FLOGIN;
我希望函数tu返回一个包含2列的表,其中包含用户访问权限中包含的表PROGRAMS_FT中的所有记录。
由于某种原因,我收到编译警告ORA-000947。 我对错误代码的理解是,当插入的值与接收值的对象的类型不匹配时会发生此错误,并且在这里我看不到这种情况。
答案 0 :(得分:0)
您正在选择两个标量值,然后尝试将它们放入对象中。这不会自动发生,您需要将它们转换为对象:
...
LOOP
SELECT PGM_ROW(PFT.ID_PROGRAM, PFT.LOCAL_TITLE)
BULK COLLECT INTO SELECTED_PGM
FROM PROGRAMS_FT PFT
...
(这是PL / SQL的一个无用的怪癖,它说“没有足够的值”而不是“太多的值”,正如您在尝试将两件事合为一体时可能期望的那样;我敢肯定,我想出了一次令人信服的解释/辩解,但此刻我不知道...)
我不确定您的循环是否有意义。假设您的游标查询返回多行,每次循环时您都将SELECTED_PGM
集合的内容替换-您可能会认为您要追加它,但这不是它的工作方式。因此,您最终将仅根据循环的最终迭代返回集合。
聚合然后拆分数据似乎也需要很多工作。您可能会为这些使用集合;但是您可能可以摆脱游标和循环的局限,并将游标查询与内部查询结合起来,这样会更高效,并且可以对所有组合数据进行单个批量收集。