Question

我有一个表，其中有一列名为“ INTERACTION_TIMESTAMP”。

我想显示该特定列中的日期和时间格式。

到目前为止，我已经尝试了以下代码：

SELECT
 USERID as UserId,
 INTERACTION_TIMESTAMP,
 EXTRACT(ISOWEEK FROM INTERACTION_TIMESTAMP) as IsoWeek,
 EXTRACT(DATE from INTERACTION_TIMESTAMP) as date,
 EXTRACT(DAYOFWEEK FROM INTERACTION_TIMESTAMP)-1 as DayOfWeek,
 PARSE_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time;
 CONCAT(CAST(JOURNEY_ID AS STRING),"-", CAST(JOURNEY_ACTIONID AS STRING)) as JobId,
CASE 
 WHEN INTERACTION_TYPE = 0 THEN "open"
 WHEN INTERACTION_TYPE = 1 THEN "click"
 ELSE null
END AS Open_Click
FROM
 `XXXXXXXXX.database_name`

但是，BigQuery总是从该行代码中发出错误消息： PARSE_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time;

该错误消息表明（据我所记得）PARSE_TIMESTAMP与该网站中显示的语法不匹配：PARSE_TIMESTAMP documentation

如何处理INTERACTION_TIMESTAMP中的字符串，以便可以在BigQuery中显示时间戳中的时间值？

谢谢

Answer 1

您可以使用EXTRACT函数提取时间并像这样传递时区

select EXTRACT(TIME FROM CURRENT_TIMESTAMP() AT TIME ZONE 'UTC') as Time;

Answer 2

以下是用于BigQuery标准SQL

您应该使用PARSE_TIMESTAMP而不是FORMAT_TIMESTAMP

SELECT
 USERID as UserId,
 INTERACTION_TIMESTAMP,
 EXTRACT(ISOWEEK FROM INTERACTION_TIMESTAMP) as IsoWeek,
 EXTRACT(DATE from INTERACTION_TIMESTAMP) as date,
 EXTRACT(DAYOFWEEK FROM INTERACTION_TIMESTAMP)-1 as DayOfWeek,
 FORMAT_TIMESTAMP("%H", INTERACTION_TIMESTAMP, "UTC") as Time,
 CONCAT(CAST(JOURNEY_ID AS STRING),"-", CAST(JOURNEY_ACTIONID AS STRING)) as JobId,
CASE 
 WHEN INTERACTION_TYPE = 0 THEN "open"
 WHEN INTERACTION_TYPE = 1 THEN "click"
 ELSE null
END AS Open_Click
FROM
 `XXXXXXXXX.database_name`

如何在BigQuery表格中的时间戳类型列中显示时间？

2 个答案: