Question

我有三个标签。在一个我想从数据库中加载数据，并通过电子邮件进行过滤。当我单击按钮时，我只希望在同一选项卡的表中显示带有电子邮件的用户的数据。

这是我的脚本

<script>
    jQuery('.savedata').click(function (e) {
        e.preventDefault();

        jQuery.post('/gettabdata', {
            _token: window.csrf_token,
            email: jQuery('input[name="email"]').val()
        } 
        function (data) {
            var $tableBody = jQuery('#filtered-data tbody');
            $tableBody.html('');

            jQuery.each(data, function (i) {
                $tableBody.append(
                    '<tr>' +
                        '<td>' + data[i].User_id + '</td>' +
                        '<td>' + data[i].email + '</td>' +
                        '<td>' + data[i].status + '</td>' +
                        '<td>' + data[i].date + '</td>' +
                        '<td>' + data[i].time + '</td>' +

                    '</tr>'
                ); 
            });
        }

        'json');
    });
</script>

这是我的控制器我想在其中查看结果的标签其他{

        $user = \Auth::guard('api')->user();
        $post = $request->all();
        $email = $request->input('email');
        $cond = ' 1=1 ';
        if(!empty($post['email'])){
        $cond .= " and email like '".$post['email']."'";
        }
        $qry = 'SELECT User_id, email, status, date, time FROM profile WHERE  '.$cond.' ';
        $data = DB::select($qry);


        $response = $this->analysis($post);
        //$getdata=$this->userdata($post);

        $data = [
        'data'=>$data,
        'response'=>$response,
        //'getdata'=>$getdata

        ];

            return response()->json($data);


    }

Answer 1

尝试

Route
Route::get('/get-record-by-email','Controller@getRecord');


//controller
    public function getRecord(Request $request)
    {
    $emailid= Input::get('email_id');

    $jsondata= DB::table(your-table)->where('email',$emailid)->get();
    return response()->json($jsondata);

    }


    //Ajax call
    $("#btnClick").change(function(e){

            //console.log(e);
            var email_id = e.target.value;

            //alert(email_id);
            //$token = $("input[name='_token']").val();
            //ajax
            $.get('/get-record-by-email?email_id='+email_id, function(data){
            $('#filterdata').empty();
            //console.log(data);
            $.each(data, function(index, obj){
            $('#filterdata').append( '<tr>'

                                          '<td>' + obj.User_id + '</td>' +
                                          '<td>' + obj.email + '</td>' +
                                          '<td>' + obj.status + '</td>' +
                                          '<td>' + obj.date + '</td>' +
                                          '<td>' + obj.time + '</td>' +

                                      '</tr>' );
              });
            })
        });

如何在单击按钮时过滤数据并在不重新加载页面的情况下显示在同一选项卡上

1 个答案: