Question

我有两个联合在一起的CTE产生以下结果：

date    serie   events
2019-05-09  hello   175
2019-05-02  hello   196
2019-05-09  goodbye 1
2019-05-02  goodbye 1

我想每天添加事件，以便

2019-05-09 total 176
2019-05-02 total 197

此刻我有类似的东西：

with hello_events as (
  --- actual logic not interesting ---
 )
 , goodbye_events as (
  --- actual logic not interesting ---
  )
select * from hello_events
union all
select * from goodbye_events

如果我希望将第三组结果作为总和，我认为我需要做类似的事情

with hello_events as (
  --- actual logic not interesting ---
 )
 , goodbye_events as (
  --- actual logic not interesting ---
  )
select * from hello_events
union all
select * from goodbye_events
union all
select date, "total", sum(events) as events
from hello_events, goodbye_events
where hello_events.date = goodbye_events.date

但这显然是不正确的。我想念什么？

Answer 1

用以下内容替换内部查询：

select date, 'total' as total, sum(events) as events
from (
        select * from hello_events
        union all
        select * from goodbye_events
    ) t
group by date

工作示例： http://www.sqlfiddle.com/#!18/b0846/4

Answer 2

仅group by，如下所示：

with hello_events as (
  --- actual logic not interesting ---
)
 ,goodbye_events as (
  --- actual logic not interesting ---
)
,tmp_result as (
select * from hello_events
union all
select * from goodbye_events
)
select
    date,
    'total',
    sum(events)
from
    tmp_result
group by
    date

从两个CTE添加SQL行

2 个答案: