Question

我有2个MySQL表

“ MerchantAccount” 它具有以下列：

提供者
二手
无效
maxPerMonth

然后我有另一个表作为跟踪器，每月使用了多少。

“商家处理” 它包含以下列： - ID -日期 -中（provider来自“ MerchantAccount”

我想要的是找到一个随机的PROVIDER，它没有使用每月的最大值，例如在“ maxPerMonth”中，例如1500个事务，那么提供者必须达到最大值。它必须按顺序打印一个随机提供程序，以便将所有事务正确分配到表中的所有提供程序上（因此使用了used + 1）。在“商家处理”表中找到在相关提供者上进行每月交易的方法。已经尝试了，但是不起作用

我尝试http://www.sqlfiddle.com/#!9/03b168/26

SELECT a.provider, a.inactive, b.mid, b.date, a.used,
   Count(b.id) AS usedThisMonth
FROM   merchantaccount a, 
   merchantprocessing b
WHERE  a.inactive = '0'
   AND ( a.provider = b.mid 
         AND Year(b.date) = Year(CURRENT_DATE()) 
         AND Month(b.date) = Month(CURRENT_DATE()) 

       ) 
       AND a.used < usedThisMonth
   ORDER  BY a.used ASC 
   LIMIT  1 `

“ where子句”中的未知列“ usedThisMonth”

Answer 1

像这样尝试：

select  IdRisorseUmane,IdUtenteInserimento,u1.Nome+' '+u1.Cognome as InseritoDA,ExtraPreventivo,
    u2.Nome+' '+u2.Cognome as             Risorsa,
    RisorseUmane.IdUtente,IdCantiere,
    CONVERT(VARCHAR(10), Data, 105) as Data,
    Descrizione,
    convert(varchar(5), OreInizio, 108) as OreInizio,
    convert(varchar(5), OreFine, 108) as OreFine,
    REPLACE(Pausa, '.', ':') as Pausa,
    convert(varchar(5),Cast(convert(varchar(5), (OreFine - OreInizio), 108) as datetime) - CAST(REPLACE(Pausa, '.', ':') as datetime), 108) as TotaleOre,
    TipologiaPreventivo.NomeTipologia as Tipologia   
from RisorseUmane  
    inner join Utente as u1  on u1.IdUtente = RisorseUmane.IdUtenteInserimento   
    inner join Utente as u2 on u2.IdUtente = RisorseUmane.IdUtente 
    inner join TipologiaPreventivo on TipologiaPreventivo.IdTipologiaPreventivo=RisorseUmane.IdTipologia

请注意，这不会产生任何行，因为它们都不满足SELECT a.provider, a.inactive, b.mid, b.date, a.used, Count(b.id) AS usedThisMonth FROM merchantaccount a, merchantprocessing b WHERE a.inactive = '0' AND ( a.provider = b.mid AND Year(b.date) = Year(CURRENT_DATE()) AND Month(b.date) = Month(CURRENT_DATE()) ) GROUP BY a.provider, a.inactive, b.mid, b.date, a.used HAVING a.used < Count(b.id) LIMIT 1子句。

Answer 2

这使您可以比较每月使用的金额和每个商人的最大金额：

select a.provider, a.inactive,
       year(p.date), month(p.date),
       count(p.id) as used_this_month,
       a.maxPerMonth
from merchantaccount a join 
     merchantprocessing p
     on a.provider = p.mid 
where a.inactive = 0  -- no quotes, because this is a number
group by a.provider, a.inactive, a.maxPerMonth,
         year(p.date), month(p.date);

您可以添加having a.maxPerMonth >= count(b.id)以获得超出最大值的数字。

您可以添加p.date >= curdate() - interval (1 - day(curdate()) day以仅获取当月的数据。

从2个表中进行选择会导致错误

2 个答案: