Question

我有一个带有A和B列的数据框。我需要编写一个函数，该函数接受A中的所有空值并根据B中的值替换它们。如果B列中的值是'很好'或“好”，则应在“ A”中放置“家”。如果B列中的值为“ Fair”或“ Bad”，则应在A中放置“ Foreign”。最后，如果B列中的值是“非常糟糕”或“最差”，则应将“中央”放在A中。

#Here's the data:
df <- structure(list(`A` = c("Home", NA, "Foreign", NA, "Central", NA), 
                 `B` = c("Good", "Very Good", "Bad", "Fair", "Very Bad", "Worst")),
            row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"))


#Here's how the data look

     A       B
1   Home    Good
2   NA  Very Good
3   Foreign Bad
4   NA  Fair
5   Central Very Bad
6   NA  Worst

#Here's the expected result
     A       B
1   Home    Good
2   Home    Very Good
3   Foreign Bad
4   Foreign Fair
5   Central Very Bad
6   Central Worst

Answer 1

library(dplyr)

df %>% mutate(tmp = case_when(B %in% c("Good", "Very Good") ~ "Home",
                              B %in% c("Bad", "Fair") ~ "Foreign",
                              B %in% c("Very Bad", "Worst") ~ "Central")) %>% 
       mutate(A = if_else(is.na(A),tmp,A)) %>% 
       select(-tmp)

#> # A tibble: 6 x 2
#>   A       B        
#>   <chr>   <chr>    
#> 1 Home    Good     
#> 2 Home    Very Good
#> 3 Foreign Bad      
#> 4 Foreign Fair     
#> 5 Central Very Bad 
#> 6 Central Worst

Answer 2

library(tidyverse)
df <- structure(list(`A` = c("Home", NA, "Foreign", NA, "Central", NA), 
                     `B` = c("Good", "Very Good", "Bad", "Fair", "Very Bad", "Worst")),
                row.names = c(NA, -6L), class = c("tbl_df", "tbl", "data.frame"))


df %>% 
  mutate(AA = ifelse(B %in% c("Good", "Very Good"), "Home", ifelse(B %in% c("Bad", "Fair"), "Foreign", ifelse(B %in% c("Very Bad", "Worst"), "Central", NA))),
  A = ifelse(is.na(A), AA, A))         
#> # A tibble: 6 x 3
#>   A       B         AA     
#>   <chr>   <chr>     <chr>  
#> 1 Home    Good      Home   
#> 2 Home    Very Good Home   
#> 3 Foreign Bad       Foreign
#> 4 Foreign Fair      Foreign
#> 5 Central Very Bad  Central
#> 6 Central Worst     Central

根据另一列中的另一行更改一行的值

2 个答案: