Question

我有一个像这样的表：

email     | segment               | exit
---------------------------------------------
1@aol.com | abandoned_cart        | true
1@aol.com | purchased_last_7_days | false
2@aol.com | abandoned_cart        | true
2@aol.com | purchased_last_7_days | false
3@aol.com | abandoned_cart        | true

我正在尝试编写查询以获取具有两个abandoned_cart = true和purchase_last_7_days = false

的唯一电子邮件地址的数量

这是我尝试过但收到的0：

SELECT COUNT(DISTINCT email)
FROM `table_seg_changes` 
WHERE (segment_slug = 'purchased_last_7_days' AND exit = false) AND (segment_slug = 'abandoned_cart' AND exit = true)

Answer 1

以下是用于BigQuery标准SQL

#standardSQL
SELECT email
FROM `project.dataset.table`
GROUP BY email 
HAVING COUNTIF(
    (segment = 'abandoned_cart' AND exit) OR 
    (segment = 'purchased_last_7_days' AND NOT exit)
  ) = 2

您可以使用问题中的示例数据来进行测试，如上示例所示

#standardSQL
WITH `project.dataset.table` AS (
  SELECT '1@aol.com' email, 'abandoned_cart' segment, TRUE exit UNION ALL
  SELECT '1@aol.com', 'purchased_last_7_days', FALSE UNION ALL
  SELECT '2@aol.com', 'abandoned_cart', TRUE UNION ALL
  SELECT '2@aol.com', 'purchased_last_7_days', FALSE UNION ALL
  SELECT '3@aol.com', 'abandoned_cart', TRUE
)
SELECT email
FROM `project.dataset.table`
GROUP BY email 
HAVING COUNTIF(
    (segment = 'abandoned_cart' AND exit) OR 
    (segment = 'purchased_last_7_days' AND NOT exit)
  ) = 2

有结果

Row email    
1   1@aol.com    
2   2@aol.com

注意：上面假设同一电子邮件的段/退出值没有重复的条目（如您的示例所示）

计算具有2个条件的唯一条目-bigquery

1 个答案: