为什么此COUNT中的“ HAVING”无法正常运行？

Question

我正在使用以下查询来选择所有出现了3次以上且状态ID为的客户。该查询还计算为客户显示状态ID的次数：

SELECT `bp_customer_id`, `status_id`, COUNT(`status_id`) FROM `bp_orders` 
GROUP BY `status_id`, `bp_customer_id` 
ORDER BY `bp_customer_id`  

它提供以下输出：

在上表中，客户1000出现3次。因此，我只选择那些在表中出现3次或3次以上的客户。我们该怎么做？我在上面的查询中使用了COUNT()和HAVING，但是没有运气。

SELECT `bp_customer_id`, `status_id`, COUNT(`status_id`) FROM `bp_orders` 
GROUP BY `status_id`, `bp_customer_id` 
HAVING COUNT(`bp_customer_id`) >= 3 
ORDER BY `bp_customer_id`

我在哪里做错了？

Answer 1

如果仅在输出结果中需要bp_customer_id，请忽略SELECT语句中的其他列

SELECT `bp_customer_id`
FROM `bp_orders` 
GROUP BY `bp_customer_id` 
HAVING COUNT(DISTINCT `bp_customer_id`) >= 3 
ORDER BY `bp_customer_id`

根据您的评论，您需要bp_customer_id以及status_id和COUNT。因此，使用以上查询作为子查询并基于bp_customer_id，您也可以获取其他详细信息。因此，有效的查询是：

​SELECT `bp_customer_id`, 
       `status_id`, 
       COUNT(`status_id`) 
FROM `bp_orders` 
WHERE `bp_customer_id` IN (
    SELECT `bp_customer_id`
    FROM `bp_orders` 
    GROUP BY `bp_customer_id` 
    HAVING COUNT(DISTINCT `bp_customer_id`) >= 3 
) 
GROUP BY `bp_customer_id`, `status_id` 
ORDER BY `bp_customer_id`

Answer 2

没有检查这是否可行，但是进行子选择可能会有帮助

SELECT A.`bp_customer_id`, A.`status_id`, COUNT(`status_id`) FROM `bp_orders` A, {
    SELECT COUNT(*) AS customerCount, `bp_customer_id` FROM `bp_orders` GROUP BY `bp_customer_id`
} B WHERE A.`bp_customer_id` = B.`bp_customer_id`
AND B.customerCount >= 3
GROUP BY A.`status_id`, A.`bp_customer_id` 
ORDER BY A.`bp_customer_id`