给我的印象是,一旦安装了bundler,就可以在Rails应用程序中的任何位置访问gem的方法。但是不是吗?我很困惑,因为在移到文件外时无法识别在controller
中可访问的方法。
有什么方法可以要求gem在command
文件而不是controller
文件中运行以下代码?
我正在使用名为sorcery
的身份验证工具来实现OAuth登录系统。 gem提供了一些methods,例如login_from(provider)
,可以从我的控制器访问它。
# app/controllers/oauths_controller.rb
class OauthsController < ApplicationController
skip_before_action :require_login
def callback
provider = params[:provider]
if @user = login_from(provider)
# method continues
end
但是,我们试图在应用程序中采用命令查询分离的方法,因此我尝试将包含login_from(provider)
方法的过程移至名为app/commands/authentication/login_command.rb
的其他文件中。这导致无法识别该方法:
NoMethodError (undefined method 'login_from' for #<Authentication::LoginCommand:>)
谢谢。
答案 0 :(得分:0)
给我的印象是,一旦安装了bundler,就可以在Rails应用程序中的任何位置访问gem的方法。
那将是一个不正确的印象。
如您所见,Sorcery::Engine
使ActionController::Base
包含Sorcery::Controller
中定义的方法,在此处:
require 'sorcery'
require 'rails'
module Sorcery
# The Sorcery engine takes care of extending ActiveRecord (if used) and ActionController,
# With the plugin logic.
class Engine < Rails::Engine
config.sorcery = ::Sorcery::Controller::Config
initializer 'extend Controller with sorcery' do
# TODO: Should this include a modified version of the helper methods?
if defined?(ActionController::API)
ActionController::API.send(:include, Sorcery::Controller)
end
if defined?(ActionController::Base)
ActionController::Base.send(:include, Sorcery::Controller)
ActionController::Base.helper_method :current_user
ActionController::Base.helper_method :logged_in?
end
end
end
end
Sorcer::Controller
依次包括一系列子模块:
module Sorcery
module Controller
def self.included(klass)
klass.class_eval do
include InstanceMethods
Config.submodules.each do |mod|
# FIXME: Is there a cleaner way to handle missing submodules?
# rubocop:disable Lint/HandleExceptions
begin
include Submodules.const_get(mod.to_s.split('_').map(&:capitalize).join)
rescue NameError
# don't stop on a missing submodule.
end
# rubocop:enable Lint/HandleExceptions
end
end
Config.update!
Config.configure!
end
...
end
end
这些子模块之一是Sourcery::Controller::Submodules::External
,如果包含,则还包括Sourcery::Controller::Submodules::External::InstanceMethods
,在这里:
module Sorcery
module Controller
module Submodules
# This submodule helps you login users from external auth providers such as Twitter.
# This is the controller part which handles the http requests and tokens passed between the app and the @provider.
module External
def self.included(base)
base.send(:include, InstanceMethods)
...
end
end
end
end
end
此外,InstanceMethods
包含方法login_from
,在这里:
module Sorcery
module Controller
module Submodules
# This submodule helps you login users from external auth providers such as Twitter.
# This is the controller part which handles the http requests and tokens passed between the app and the @provider.
module External
def self.included(base)
base.send(:include, InstanceMethods)
module InstanceMethods
protected
...
# tries to login the user from provider's callback
def login_from(provider_name, should_remember = false)
sorcery_fetch_user_hash provider_name
return unless (user = user_class.load_from_provider(provider_name, @user_hash[:uid].to_s))
# we found the user.
# clear the session
return_to_url = session[:return_to_url]
reset_sorcery_session
session[:return_to_url] = return_to_url
# sign in the user
auto_login(user, should_remember)
after_login!(user)
# return the user
user
end
...
end
end
end
end
end
Soooo,这是一个很长的说法,login_from
在从ActionController::Base
继承的类上被定义为受保护的实例方法,而在不从{继承的类上被定义为实例方法。 {1}},这就是为什么您获得ActionController::Base
的原因。
我是否可以通过某种方式要求gem在命令文件中而不是控制器中运行以下代码?
也许。也许不吧。如您所见,NoMethodError
正在使用其他login_from
方法和从sorcery
继承的方法。因此,您需要确保ActionController::Base
中所有这些方法都可用,以便Authentication::LoginCommand
正常运行。