很抱歉，如果这是一个菜鸟问题。我想减少数组元素的值。
我指定了此数组以获取值-> May 20 2019 00:00:00 GMT+0800 (Philippine Standard Time)并返回this.helper.workingExperienceList[0]["start_date"].replace(/00:00:00 GMT+0800 (Philippine Standard Time)/g, "")
我尝试使用此May 20 2019，但有一个不是函数的错误。
预期输出应为import re
s = "Too many people, but not All Awesome Dudes (AAD) only care about the Initiative on Methods, Measurement, and Pain Assessment in Clinical Trials (IMMPACT)."
allabbre = []
for match in re.finditer(r"\((.*?)\)", s):
start_index = match.start()
abbr = match.group(1)
size = len(abbr)
words = s[:start_index].split()
count=0
for k,i in enumerate(words[::-1]):
if i[0].isupper():count+=1
if count==size:break
words=words[-k-1:]
definition = " ".join(words)
abbr_keywords = definition + " " + "(" + abbr + ")"
pattern='[A-Z]'
if re.search(pattern, abbr):
if abbr_keywords not in allabbre:
allabbre.append(abbr_keywords)
print(abbr_keywords)
请帮助！