我有一个带有一列字符串的数据框,我想将其进一步标记为以下类别:城市,国家和大洲。我用gsub将所有城市替换为“城市”,将所有国家替换为“国家”,并将所有大洲替换为“大陆”。
#This is what I have
dataframe
Color Letter Words
red A Paris,Asia,parrot,Antarctica,North America,cat,lizard
blue A Panama,New York,Africa,dog,Tokyo,Washington DC,fish
red B Copenhagen,bird,USA,Japan,Chicago,Mexico,insect
blue B Israel,Antarctica,horse,South America,North America,turtle,Brazil
#This is what I want
dataframe
Color Letter New
red A City,Continent
blue A Country,City,Continent
red B City,Country
blue B Country,Continent
#This is the code I have so far
dataframe$New <- NA
#groups all the cities
dataframe$New <- lapply)dataframe$Words, function(x) {
gsub("Paris|New York|Tokyo|Washington DC|Copenhagen|Chicago", "City", x)})
#groups all the countries
dataframe$New <- lapply)dataframe$Words, function(x) {
gsub("Panama|USA|Japan|Mexico|Israel|Brazil", "Country", x)})
#groups all the continents
dataframe$New <- lapply)dataframe$Words, function(x) {
gsub("Asia|Antarctica|Africa|North America|South America", "Continent", x)})
dataframe$Words <- NULL
如何保持每次在dataframe $ New中的覆盖,以及如何删除多余的单词(例如鱼,马,猫)?
以上数据是基于非常大的数据集的示例。在数据集中,单词列有很多重复。请参阅下面的dataframe $ Words中的一些示例行:
Words
Panama,Paris
Panama,Israel,cat
Panama,Paris,horse,
Panama,Asia
Panama
Panama,Chicago
Israel,Chicago
Israel,lizard,Paris
Israel,Panama,horse,Africa
```
答案 0 :(得分:1)
考虑粘贴几个ifelse
调用以检查特定字符串:
dataframe$New <- paste(ifelse(grepl("Paris|New York|Tokyo|Washington DC|Copenhagen|Chicago", dataframe$Words), "City", "N/A"),
ifelse(grepl("Panama|USA|Japan|Mexico|Israel|Brazil", dataframe$Words), "Country", "N/A"),
ifelse(grepl("Asia|Antarctica|Africa|North America|South America", dataframe$Words), "Continent", "N/A"),
sep=",")
dataframe$New <- gsub("N/A,|,N/A", "", dataframe$New)
dataframe
# Color Letter Words New
# 1 red A Paris,Asia,parrot,Antarctica,North America,cat,lizard City,Continent
# 2 blue A Panama,New York,Africa,dog,Tokyo,Washington DC,fish City,Country,Continent
# 3 red B Copenhagen,bird,USA,Japan,Chicago,Mexico,insect City,Country
# 4 blue B Israel,Antarctica,horse,South America,North America,turtle,Brazil Country,Continent
或带有do.call
+ lapply
的烘干机版本:
strs <- list(c("Paris|New York|Tokyo|Washington DC|Copenhagen|Chicago", "City"),
c("Panama|USA|Japan|Mexico|Israel|Brazil", "Country"),
c("Asia|Antarctica|Africa|North America|South America", "Continent"))
df$New2 <- do.call(paste,
c(lapply(strs, function(s) ifelse(grepl(s[1], df$Words), s[2], "N/A")),
list(sep=",")))
df$New2 <- gsub("N/A,|,N/A", "", df$New2)
答案 1 :(得分:0)
最好创建一个{/ {1}}键/值对,然后在替换后通过匹配'键'提取元素
list
将与library(gsubfn)
# key val list
lst1 <- list(Paris = "City", `New York` = "City", Tokyo = "City",
`Washington DC` = "City",
Copenhagen = "City", Chicago = "City", Panama = "Country",
USA = "Country", Japan = "Country", Mexico = "Country", Israel = "Country",
Brazil = "Country", Asia = "Continent", Antarctica = "Continent",
Africa = "Continent", `North America` = "Continent",
`South America` = "Continent")
的匹配值提取到strapply
中,并用list
和list
的{{1}}字符串遍历sapply
“城市”,“大陆”或“国家”
paste
unique