Question

我正在使用SceneBuilder制作项目的GUI。我有JavaFx知识，但对FXML的了解很少。我已经建立了父窗口，控制器类和主类。我的父窗口AdminView应该具有一个功能按钮，该按钮会指向另一个窗口。但是，我无法使父窗口显示出来。

我认为这可能与库或URL参考有关。但是我对这个话题还不了解，该怎么做。

我的主班：


    @Override
    public void start(Stage primaryStage) throws Exception {
        Parent root = FXMLLoader.load(getClass().getResource("/application/view/Adminview.fxml"));

        primaryStage.setScene(new Scene(root));
        primaryStage.show();
    }

    public static void main(String[] args) {
        Application.launch(args);
    }
}

我的控制器：

public abstract class AdminViewController implements Initializable {

    @FXML
    private void Button(ActionEvent event) {
        {
            try {
                Parent AdminViewParent = FXMLLoader.load(getClass().getResource("/application/view/Addhotel.fxml"));
                Scene AdminViewScene = new Scene(AdminViewParent);

                Stage window = (Stage) ((Node) event.getSource()).getScene().getWindow();

                window.setScene(AdminViewScene);
                window.show();
            } catch (IOException e) {
                System.out.println("Something went wrong.");
            }

        }
    }
}

例外：

Exception in Application start method
java.lang.reflect.InvocationTargetException
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:498)
    at com.sun.javafx.application.LauncherImpl.launchApplicationWithArgs(LauncherImpl.java:389)
    at com.sun.javafx.application.LauncherImpl.launchApplication(LauncherImpl.java:328)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:498)
    at sun.launcher.LauncherHelper$FXHelper.main(LauncherHelper.java:767)
Caused by: java.lang.RuntimeException: Exception in Application start method
    at com.sun.javafx.application.LauncherImpl.launchApplication1(LauncherImpl.java:917)
    at com.sun.javafx.application.LauncherImpl.lambda$launchApplication$154(LauncherImpl.java:182)
    at java.lang.Thread.run(Thread.java:748)
Caused by: java.lang.NullPointerException: Location is required.
    at javafx.fxml.FXMLLoader.loadImpl(FXMLLoader.java:3207)
    at javafx.fxml.FXMLLoader.loadImpl(FXMLLoader.java:3175)
    at javafx.fxml.FXMLLoader.loadImpl(FXMLLoader.java:3148)
    at javafx.fxml.FXMLLoader.loadImpl(FXMLLoader.java:3124)
    at javafx.fxml.FXMLLoader.loadImpl(FXMLLoader.java:3104)
    at javafx.fxml.FXMLLoader.load(FXMLLoader.java:3097)
    at view.AdminView.start(AdminView.java:13)
    at com.sun.javafx.application.LauncherImpl.lambda$launchApplication1$161(LauncherImpl.java:863)
    at com.sun.javafx.application.PlatformImpl.lambda$runAndWait$174(PlatformImpl.java:326)
    at com.sun.javafx.application.PlatformImpl.lambda$null$172(PlatformImpl.java:295)
    at java.security.AccessController.doPrivileged(Native Method)
    at com.sun.javafx.application.PlatformImpl.lambda$runLater$173(PlatformImpl.java:294)
    at com.sun.glass.ui.InvokeLaterDispatcher$Future.run(InvokeLaterDispatcher.java:95)
    at com.sun.glass.ui.win.WinApplication._runLoop(Native Method)
    at com.sun.glass.ui.win.WinApplication.lambda$null$147(WinApplication.java:177)
    ... 1 more
Exception running application view.AdminView
C:\Users\loku\AppData\Local\NetBeans\Cache\8.2\executor-snippets\run.xml:53: Java returned: 1
BUILD FAILED (total time: 2 seconds)

Answer 1

    public class Class extends Application {

public static void main(String[] args) {
    launch(args);
}

@Override
public void start(Stage primaryStage) {
    try {
        // Load root layout from fxml file.
        FXMLLoader loader = new FXMLLoader();

        loader.setLocation(this.getClass().getResource("/Folder/File.fxml"));
        loader.setController(LoginController.class);

        Parent parent = loader.load();

        // Show the scene containing the root layout.
        Scene scene = new Scene(parent);
        primaryStage.setScene(scene);
        primaryStage.show();
    } catch (IOException e) {
        e.printStackTrace();
    }
}

这一直对我有用！当您要打开新窗口时，请使用它！如果要将FXML添加到窗格中，请使用此选项：

public void showFXML() {
    try {
        // Load root layout from fxml file.
        FXMLLoader loader = new FXMLLoader();

        loader.setLocation(this.getClass().getResource("/layout/YourFXML.fxml"));
        loader.setController(new YourController());
        //yourController = loader.getController();

        yourParent = loader.load();

        //yourMainController.getPane().getChildren().clear();
        yourMainController.getPane().getChildren().add(yourParent);
    } catch (IOException e) {
        e.printStackTrace();
    }
}

然后这是我的控制器：

public class Controller {
@FXML
Pane pane;

@FXML
Button button;

@FXML
private void buttonOnClicked() {
    doSomething()
}
}

为此，您必须在“代码”下的SceneBuilder中添加方法名称。

希望我能为您提供帮助！

如何使我的FXML文件显示在窗口上？

1 个答案: