Question

原谅我缺乏知识的人，尽管我前一段时间对C＃有点涉猎，但我是一名数据库专家。我试图弄清楚如何使此API运行。

我要使用的API来自{{3}}。几乎没有任何文档可以指导我。

这是我的代码：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using unirest_net.http;
using unirest_net;

namespace NBA_test
{
    class Program
    {
        public static void Main(string[] args)
        {
            Console.WriteLine("Start ...");

            Task<HttpResponse<MyClass.RootObject>> response = Unirest.get("https://api-nba-v1.p.rapidapi.com/gameDetails/5162")
            .header("X-RapidAPI-Host", "api-nba-v1.p.rapidapi.com")
            .header("X-RapidAPI-Key", "myKey")
            .asJsonAsync<MyClass.RootObject>();

            var status = response.Status;

            Console.WriteLine("End ....");
        }
    }

    public class MyClass
    {
        public class Result
        {
            public string seasonYear { get; set; }
            public int gameId { get; set; }
            public string arena { get; set; }
        }

        public class RootObject
        {
            public List<Result> results { get; set; }
        }
    }
}

var状态从“已创建”变为“正在运行”，就这样，程序关闭。没有错误消息，但我不知道如何从该API中获取JSON。我知道我想念什么，但不知道。

Answer 1

您正在使用sync主要方法在控制台应用程序中。您不应该在async方法内调用sync方法。我将您的async通话变成了sync通话：

    public static void Main(string[] args)
    {
        Console.WriteLine("Start ...");

        var response = Unirest.get("https://api-nba-v1.p.rapidapi.com/gameDetails/5162")
        .header("X-RapidAPI-Host", "api-nba-v1.p.rapidapi.com")
        .header("X-RapidAPI-Key", "myKey")
        .asJson<RootObject>();

        var status = response.Status;

        Console.WriteLine("End ....");
    }

您仍然可能会问反序列化的JSON在哪里？

根据Unirest docs：

回复   收到响应后，Unirest会在   对象的形式，此对象应始终具有相同的键   有关回复详细信息的每种语言。

.Code-HTTP响应状态代码（示例200）   .Headers-HTTP   响应标题   .Body-解析的响应正文（如果适用）   JSON响应示例将解析为对象/关联数组。   .Raw-未解析的响应正文

基本上，您可以像这样访问结果：

if (response.Code == 200) // Success, OK in HTTP Codes
{
  response.Body; // which body has the type of MyClass.RootObject
}

完整的示例：

        public static void Main(string[] args)
        {
            Console.WriteLine("Start ...");

            var response = Unirest.get("https://api-nba-v1.p.rapidapi.com/gameDetails/5162")
            .header("X-RapidAPI-Host", "api-nba-v1.p.rapidapi.com")
            .header("X-RapidAPI-Key", "myKey")
            .asJson<RootObject>();

            if (response.Code == 200) // Success, OK in HTTP Codes
            {
              response.Body; // which body has the type of MyClass.RootObject
            }

            Console.WriteLine("End ....");

            Console.ReadLine(); // to force command line stay up for an input and not close applicaiton immediately aftter runing it.
        }

更新1：

这是Unirest在.NET Fiddle上的现场直播和工作：

https://dotnetfiddle.net/EZDopa

Answer 2

正如其他人指出的那样，您需要添加一些等待语句。我对api进行了许多调用，这些调用花费了一些时间在我的一个应用程序中进行处理。根据其他评论，我进行了更新，以允许您在等待调用返回时执行逻辑。您对代码的修改是：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using unirest_net.http;
using unirest_net;

namespace NBA_test
{
class Program
{
    public static void Main(string[] args)
    {
        Console.WriteLine("Start ...");
        //the added Wait() causes the thread to hold until the task is finished.
        Task<HttpResponse<MyClass.RootObject>> response = Unirest.get("https://api-nba-v1.p.rapidapi.com/gameDetails/5162")
        .header("X-RapidAPI-Host", "api-nba-v1.p.rapidapi.com")
        .header("X-RapidAPI-Key", "myKey")
        .asJsonAsync<MyClass.RootObject>();


        //if need to perform other logic while you are waiting
        while(response.Status == TaskStatus.Running)
        {
         // perform other logic like gui here
        }
        var status = response.Status;

        Console.WriteLine("End ....");
    }
}

public class MyClass
{
    public class Result
    {
        public string seasonYear { get; set; }
        public int gameId { get; set; }
        public string arena { get; set; }
    }

    public class RootObject
    {
        public List<Result> results { get; set; }
    }
}

}

Answer 3

您可以使用httpClient

   using (var httpClient = new HttpClient())
        {
            httpClient.DefaultRequestHeaders.Add("User-Agent", "Mozilla/5.0 (Windows NT 6.1; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.36");
            var response = httpClient.GetStringAsync(new Uri(url)).Result;
            var releases = JArray.Parse(response);
        }

Answer 4

原来，该API的文档存在缺陷。我设法通过简单地使用字符串（和Newtonsoft的Json.NET）使其工作。谢谢@AliBahrami。代码现在看起来像这样：

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using unirest_net.http;
using unirest_net;
using Newtonsoft.Json.Linq;

namespace NBA_test
{
    public class Program
    {

        public static void Main(string[] args)
        {

            Console.WriteLine("Start of Program...");

            HttpResponse<string> response = Unirest.get("https://api-nba-v1.p.rapidapi.com/gameDetails/9999")
            .header("X-RapidAPI-Host", "api-nba-v1.p.rapidapi.com")
            .header("X-RapidAPI-Key", "myKey")
            .asJson<string>();

            var result = response.Body;

            JObject parsedString = JObject.Parse(result);

            RootObject myGame = parsedString.ToObject<RootObject>();

            // Get game id
            Console.WriteLine(myGame.results[0].gameId);

            Console.WriteLine("End of Program....");
        }
    }
}

无法弄清楚如何在C＃中使用此API

4 个答案: