Question

这就是我想要做的：

@SpringBootApplication public class App {
    public static final String NAME;

    public static void main(String[] args) {
        SpringApplication.run(App.class, args);
    }

    @Autowired public App(ApplicationArguments arguments) {
        NAME = arguments.getSourceArgs()[0]; // ERROR (1)
    }

    @GetMapping("/" + NAME) public void test() { // ERROR (2)
        return NAME;
    }
}

该代码无法正常工作，因为（1）无法分配NAME，并且（2）@GetMapping的注释值必须是一个常量表达式。

我只希望@GetMapping使用基于命令行参数的值。该怎么办？

Answer 1

在第一个请求中。 spring mvc将初始化资源。所以您将动态网址放入haddlermapping中。

我们需要三个班级。 MyController MyDispatcherServlet DispatcherServletCustomConfiguration

MyController.java

@Component(value="MyController")
public class MyController {

@Autowired
ClaimService claimService;

public ResponseEntity<HttpStatus> insertClaim() {
    return new ResponseEntity<>(HttpStatus.OK);
    }

}

MyDispatcherServlet.java。在initStrategies.put之后，您的动态网址将进入handdlerMapping。

public class MyDispatcherServlet extends DispatcherServlet {

private String url;


public MyDispatcherServlet(String url) {
    super();
    this.url = url;
}


@Override
protected void onRefresh(ApplicationContext context) {
    initStrategies(context);
    List<HandlerMapping> handlerMappings = getHandlerMappings();
    for (HandlerMapping handlerMapping : handlerMappings) {

        if (handlerMapping instanceof RequestMappingHandlerMapping) {
            RequestMappingHandlerMapping requestMappingHandlerMapping = ((RequestMappingHandlerMapping) handlerMapping);
            RequestMappingInfo.Builder n = RequestMappingInfo
                    .paths(url)
                    .methods(RequestMethod.GET);
            try {
                Method method = MyController.class.getDeclaredMethod("insertClaim");
                requestMappingHandlerMapping.registerMapping(n.build(), "MyController", method);
            } catch (NoSuchMethodException e) {
                e.printStackTrace();
            }

        }
    }

}


}

DispatcherServletCustomConfiguration.java

@Configuration
public class DispatcherServletCustomConfiguration {

@Value("${myUrl}")
private String url;

@Bean
public DispatcherServlet dispatcherServlet() {
    return new MyDispatcherServlet(url);
   }

}

使用命令java -jar stackoverflow-1.0-SNAPSHOT.jar --myUrl=abcd

运行

Spring Boot：如何将命令行参数传递给注释值？

1 个答案: