在Python中解析Salesforce.com XML消息

时间:2019-06-02 20:09:41

标签: python xml soap salesforce

我正在尝试连接Python和Salesforce。

Salesforce向我发送了一条出站SOAP消息,我可以正确接收,确认和阅读该消息。

现在,我想解析消息以确定在Python中触发什么脚本。

以下是收到的邮件正文的印刷示例:(我用XXX标识了ID)

b'<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
 <soapenv:Body>
  <notifications xmlns="http://soap.sforce.com/2005/09/outbound">
   <OrganizationId>00Dxxxx</OrganizationId>
   <ActionId>04k5A000000XXX</ActionId>
   <SessionId xsi:nil="true"/>
   <EnterpriseUrl>https://xxx-dev-ed.my.salesforce.com/services/Soap/c/45.0/00Dxxxx </EnterpriseUrl>
   <PartnerUrl>https://xxx-dev-ed.my.salesforce.com/services/Soap/u/45.0/00Dxxxx </PartnerUrl>
   <Notification>
    <Id>04l5A000XXX</Id>
    <sObject xsi:type="sf:QuoteHistory__c" xmlns:sf="urn:sobject.enterprise.soap.sforce.com">
     <sf:Id>a0B5A0XXX</sf:Id>
     <sf:Status__c>Send price request</sf:Status__c>
    </sObject>
   </Notification>
  </notifications>
 </soapenv:Body>
</soapenv:Envelope>'

str前面的b是什么?当我打印消息正文时,Python会打印它。有影响吗?

现在,要处理我的消息,我想阅读sObject选项卡中的行,即示例中的行:

    <sObject xsi:type="sf:QuoteHistory__c" xmlns:sf="urn:sobject.enterprise.soap.sforce.com">
     <sf:Id>a0B5A0XXX</sf:Id>
     <sf:Status__c>Send price request</sf:Status__c>
    </sObject>

有时候,我希望我的消息具有除“状态”和“发送的ID”以外的其他字段,我希望将消息正确地解析到表中,然后根据所发送的字段及其值确定要触发的操作。

我将管理一个包含字段名称/字段值和要触发的操作的表,这对我来说似乎很容易。

正确正确地动态读取此消息的最佳方法是什么?

2 个答案:

答案 0 :(得分:1)

在下面看看

import re
import xml.etree.ElementTree as ET

XML = '''<?xml version="1.0" encoding="UTF-8"?>
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
 <soapenv:Body>
  <notifications xmlns="http://soap.sforce.com/2005/09/outbound">
   <OrganizationId>00Dxxxx</OrganizationId>
   <ActionId>04k5A000000XXX</ActionId>
   <SessionId xsi:nil="true"/>
   <EnterpriseUrl>https://xxx-dev-ed.my.salesforce.com/services/Soap/c/45.0/00Dxxxx </EnterpriseUrl>
   <PartnerUrl>https://xxx-dev-ed.my.salesforce.com/services/Soap/u/45.0/00Dxxxx </PartnerUrl>
   <Notification>
    <Id>04l5A000XXX</Id>
    <sObject xsi:type="sf:QuoteHistory__c" xmlns:sf="urn:sobject.enterprise.soap.sforce.com">
     <sf:Id>a0B5A0XXX</sf:Id>
     <sf:Status__c>Send price request</sf:Status__c>
    </sObject>
   </Notification>
  </notifications>
 </soapenv:Body>
</soapenv:Envelope>'''

_xml = xmlstring = re.sub(' xmlns="[^"]+"', '', XML, count=1)
tree = ET.fromstring(_xml)
sobject = tree.find('.//sObject')
for idx, child in enumerate(list(sobject)):
    print('{}) {} => {}'.format(idx, child.tag[child.tag.find('}') + 1:], child.text))

输出

0) Id => a0B5A0XXX
1) Status__c => Send price request

答案 1 :(得分:0)

使用xmltodict找到了我的方式

import pandas as pd 
import xmltodict

#Convert the msg to dict
ParsedSFMessage = xmltodict.parse(sfmsg)
#Keep only the needed level
ParsedSFMessage = ParsedSFMessage['soapenv:Envelope']['soapenv:Body']['notifications']['Notification']['sObject'] 
#Convert to df and transpose
ParsedSFMessage = pd.DataFrame.from_dict(ParsedSFMessage, orient='index').T.drop(columns = ['@xmlns:sf'])

Etvoilà

@xsi:type   sf:Id   sf:Status__c
sf:QuoteHistory__c  a0B5A0XXXX  Send price request