Question

Firebase实时数据库无法在setValue中保存EditText字符串或String test_case =“这是测试用例消息”，但已成功保存了databaseReference.child（id_key）.setValue（“ given string text”）;

                 final Text_Strings text_strings = new Text_Strings(user_name, id_key, title_m, question_m);



               // to save elements database referefernce called
                    databaseReference.child(id_key).setValue(text_strings, new DatabaseReference.CompletionListener() {
                    @Override
                    public void onComplete(DatabaseError databaseError, DatabaseReference databaseReference) {
                        if (databaseError != null) {
                            Log.d("Data could not be saved ", databaseError.getMessage());
                        } else {
                            // it is always saying data
                            Toast.makeText(getContext(), "Data saved  succcessfully ", Toast.LENGTH_SHORT).show();
                        }
                    }
                });
                    // to save id_key for test cases
                databaseReference.child(id_key).setValue(test_case);
           /// to save string elements for test cases
                databaseReference.child(id_key).setValue("given string text");



            }
        });

  // return view
        return  view;
    }
}

;

Answer 1

检查您是否处于测试模式或正确应用了读写规则。

您可以参考文档以在Firebase Realtime数据库中读取和写入数据：https://firebase.google.com/docs/database/android/read-and-write

请粘贴您完整的活动代码，以更好地了解您的问题。

Firebase数据库无法保存EditText字符串或String文本，

1 个答案: