我有这种数据
[ {
"camera_name": "Bolands Mills Arup",
"exid": "bolands-mills-arup",
"latest_snapshot_date": "2019-05-30T07:06:55+01:00",
"oldest_snapshot_date": "2015-12-24T23:33:23+00:00",
"years": {
"2015": [
"12"
],
"2016": [
"04",
"08",
"09",
"10",
"02",
"06",
"03",
"11",
"12",
"01",
"07",
"05"
],
"2017": [
"04",
"07",
"10",
"09",
"11",
"01",
"02",
"03",
"05",
"06",
"08",
"11",
"12"
],
"2018": [
"03",
"05",
"06",
"10",
"11",
"01",
"02",
"08",
"09",
"04",
"07",
"11",
"12"
],
"2019": [
"01",
"02",
"03",
"04",
"05"
]
}
},
{
"camera_name": "Walls Demo",
"exid": "central-bank-fusion",
"latest_snapshot_date": "2019-05-30T07:07:02+01:00",
"oldest_snapshot_date": "2015-11-08T16:30:48+00:00",
"years": {
"2015": [
"12",
"11"
],
"2016": [
"02",
"03",
"05"
],
"2017": [
"03",
"08",
"10",
"02",
"04",
"05",
"06",
"07",
"09",
"11",
"01",
"11",
"12"
],
"2018": [
"03",
"04",
"07",
"09",
"01",
"02",
"08",
"10",
"11",
"05",
"06",
"11",
"12"
],
"2019": [
"01",
"02",
"03",
"04",
"05"
]
}
}
]
起初，我试图用年份值格式化该数据，结果就是这样。
[
{
"camera_name": "Bolands Mills Arup",
"exid": "bolands-mills-arup",
"latest_snapshot_date": "2019-05-30T07:06:55+01:00",
"oldest_snapshot_date": "2015-12-24T23:33:23+00:00",
"oct": 1,
"nov": 1,
"dec": 1,
"jan": 1,
"feb": 1,
"mar": 1,
"apr": 1,
"may": 1,
"jun": 1,
"jul": 1,
"aug": 1,
"sep": 1
},
{
"camera_name": "Walls Demo",
"exid": "central-bank-fusion",
"latest_snapshot_date": "2019-05-30T07:07:02+01:00",
"oldest_snapshot_date": "2015-11-08T16:30:48+00:00",
"oct": 0,
"nov": 0,
"dec": 0,
"jan": 0,
"feb": 1,
"mar": 1,
"apr": 0,
"may": 1,
"jun": 0,
"jul": 0,
"aug": 0,
"sep": 0
}
]
这是当用户仅选择一年（例如2016年）时，那么将生成上述结果。现在，我正在尝试编制诸如以下数据。
{
"camera_name": "Walls Demo",
"exid": "central-bank-fusion",
"latest_snapshot_date": "2019-05-30T07:07:02+01:00",
"oldest_snapshot_date": "2015-11-08T16:30:48+00:00",
"2015-jan": 0,
"2015-feb": 0,
....
"2015-nov": 1,
"2015-dec": 1,
"2016-jan": 0,
"2016-feb": 1,
so on ...
}
在5年的12个月中，大约会有60列。
这是我用来制作以第二种模式显示的数据的方法
formatDataWithYear(cameras) {
let months_chars = {
"01":"jan",
"02":"feb",
"03":"mar",
"04":"apr",
"05":"may",
"06":"jun",
"07":"jul",
"08":"aug",
"09":"sep",
"10":"oct",
"11":"nov",
"12":"dec"
}
let year = this.year;
var obj = cameras.map(({years, ...obj}) => {
var months = years[year]
for(var i in months_chars) {
months.includes(i) ? obj[months_chars[i]] = 1 : obj[months_chars[i]] = 0
}
return obj
});
return obj;
}
答案 0 :(得分：0)
要包含所有年份，您可以像这样运行其他循环：
{{1}}
答案 1 :(得分：0)
使用Object.entries将帮助我们更轻松地映射值：
const cameras = [{
"camera_name": "Bolands Mills Arup",
"exid": "bolands-mills-arup",
"latest_snapshot_date": "2019-05-30T07:06:55+01:00",
"oldest_snapshot_date": "2015-12-24T23:33:23+00:00",
"years": {
"2015": [
"12"
],
"2016": [
"04",
"08",
"09",
"10",
"02",
"06",
"03",
"11",
"12",
"01",
"07",
"05"
],
"2017": [
"04",
"07",
"10",
"09",
"11",
"01",
"02",
"03",
"05",
"06",
"08",
"11",
"12"
],
"2018": [
"03",
"05",
"06",
"10",
"11",
"01",
"02",
"08",
"09",
"04",
"07",
"11",
"12"
],
"2019": [
"01",
"02",
"03",
"04",
"05"
]
}
},
{
"camera_name": "Walls Demo",
"exid": "central-bank-fusion",
"latest_snapshot_date": "2019-05-30T07:07:02+01:00",
"oldest_snapshot_date": "2015-11-08T16:30:48+00:00",
"years": {
"2015": [
"12",
"11"
],
"2016": [
"02",
"03",
"05"
],
"2017": [
"03",
"08",
"10",
"02",
"04",
"05",
"06",
"07",
"09",
"11",
"01",
"11",
"12"
],
"2018": [
"03",
"04",
"07",
"09",
"01",
"02",
"08",
"10",
"11",
"05",
"06",
"11",
"12"
],
"2019": [
"01",
"02",
"03",
"04",
"05"
]
}
}
]
let months_chars = {
"01": "jan",
"02": "feb",
"03": "mar",
"04": "apr",
"05": "may",
"06": "jun",
"07": "jul",
"08": "aug",
"09": "sep",
"10": "oct",
"11": "nov",
"12": "dec"
}
// Map over every camera object in the array,
// and deconstruct the object to give us the years, and the rest of the object.
var obj = cameras.map(({years, ...obj}) => {
// Loop over each entry from the years object,
// and deconstruct the array into a key/value pair:
// e.g. [year, months] => 2016, [01,02,03] etc
Object.entries(years).forEach(([year, months]) => {
// Then loop over each entry in the months_chars object,
// and deconstruct the array into another key/value pair:
// e.g. [key, month] => 01, "jan"
Object.entries(months_chars).forEach(([key, month]) => {
// Check if the months value from earlier has the specified month,
// and set the objects's value to 1 or 0 accordingly
obj[`${year}-${month}`] = months.includes(key) ? 1 : 0
})
})
return obj
})
console.log(obj)