两个输入足以使程序运行,但在极少数情况下,会使用第三个输入C,但其他时间取决于C和A的长度。
A = int(input("Enter A:"))
B = int(input("Enter B:"))
tempC = input("Enter C:(If None press Enter)")
C = ""
counter1 = len(str(A))
counter2 = len(str(B))
print("counter value is:" + str(counter1)+ " and " + str(counter2))
print("temp value is:" + str(tempC))
if counter1 == counter2:
if tempC and (counter1 == 1):
C = "10"
elif tempC and (counter1 == 2):
C = "100"
elif tempC and (counter1 == 3):
C = "1000"
else:
print("Lengths are not same")
print("Value of C is: " + str(C))
期望的输出-当按下enter键并且counter1 = 2
Enter A:45
Enter B:54
Enter C:(If None press Enter)
counter value is:2 and 2
temp value is:
Value of C is: 100
获得的输出
Enter A:45
Enter B:45
Enter C:(If None press Enter)
counter value is:2 and 2
temp value is:
Value of C is:
答案 0 :(得分:0)
我认为您应该尝试:
if tempC=="" and (counter1 == 2):
这应该可以解决您的问题。
此外,C已经是一个字符串,因此您可以简单地使用C
而不是str(C)
。
因此,根据您的修改,您的代码是:
A = int(input("Enter A:"))
B = int(input("Enter B:"))
tempC = input("Enter C:(If None press Enter)")
C = ""
counter1 = len(str(A))
counter2 = len(str(B))
print("counter value is:" + str(counter1)+ " and " + str(counter2))
print("temp value is:" + str(tempC))
if counter1 == counter2:
if tempC=="" and (counter1 == 1):
C = "10"
elif tempC=="" and (counter1 == 2):
C = "100"
elif tempC=="" and (counter1 == 3):
C = "1000"
elif tempC=="" and (counter1 == 4):
C = "10000"
else:
print("Lengths are not same")
print("Value of C is: " + str(C))