Question

我有以下数组，它充满了乱语（我厌倦了使用lorem ipsum所以我开始输入随机的东西 - 我正在测试¬_¬）。

我用mysqli_fetch_array来获取这个数组。

[ARRAY1]

Array
(
    [0] => Array
        (

            [title] => this is a new thread, and it is great and it should work

            [thread_id] => 27

            [content] => <p>hello, how are you? and what are you doing y'all and this should work</p> 

            [username] => umar

            [author_id] => 12

            [tags] => Array
                (
                    [0] => lorem
                )

        )

    [1] => Array
        (

            [title] => this is my second thread and it should work fine, just fine

            [thread_id] => 28

            [content] => <p>this is is good, that I think it should have a thread of its own, don't you think?</p> 

            [username] => umarrazzaq

            [author_id] => 12

            [tags] => Array
                (
                    [0] => thread
                    [1] => less
                )

        )

)

我有另一个数组[array2]：

    Array ( [0] => Array (  [replies] => 2  [id] => 27 )
 [1] => Array (  [replies] => 1  [id] => 28 ) )

我想将第二个数组推送到ID匹配的第一个数组。

e.g。

所以第一个数组将成为：

 [0] => Array
            (

                [title] => this is a new thread, and it is great and it should work

                [thread_id] => 27

                [content] => <p>hello, how are you? and what are you doing y'all and this should work</p> 

                [username] => umar

                [author_id] => 12

                [tags] => Array
                    (
                        [0] => lorem
                    )

                **[replies] => 2**

            )

我尝试通过引用传递并在foreach循环中使用array_push，但它只能用于一个。

Answer 1

试试这个：

foreach($array1 as $key=>&$arr){
    $arr['replies'] = $array2[$key]['replies']
}

Answer 2

您似乎也可以通过桌面上的JOIN进行此操作

foreach($array1 as $key => $value)
    {
     $array1[$value['thread_id']] = $value;

    }

    foreach($array2 as $value)
    {
      array_push($array1[$value['id']], $value);
    }

Answer 3

如果我的问题正确，那么你想合并array2.id和array1.thread_id相同的数组。在这种情况下，您不能使用array_merge。除非您将第二个数组更改为如下所示。

阵列（ [$ thead_id] =＆gt;数组（[回复] =＆gt; 2） .... ）那么你可以轻松使用array_merge。

将值推送到数组的末尾

3 个答案: