我在SQL Server中有一个查询,该查询搜索可用的服务提供商以进行以下预定:
您可以在此图中看到详细信息:
该查询对于找出哪些服务具有开放时隙非常昂贵
--select * from ServiceProvider where Id > = 636 and CityId = 4
DECLARE @longx NVARCHAR(20);
DECLARE @laty NVARCHAR(20);
DECLARE @userCityId INT;
DECLARE @userLocation GEOMETRY;
Declare @serviceName NVARCHAR(50);
declare @startDate AS DATE;
declare @endDate AS DATE;
SET @longx = '24.72977896594770';
SET @laty = '46.82470379239910';
SET @userCityId = 4;
SET @serviceName = '%hair%'
SET @userLocation = geometry::STPointFromText('POINT(' + @laty + ' ' + @longx + ')',0);
SET @startDate = '2019-06-01';
SET @endDate = '2019-06-05';
DECLARE @compareParts AS INT;
SET @compareParts = DATEDIFF(DAY, @startDate, @endDate) * 40 ;
-- get all services like serviceName
-- find out which SP offer them
-- find out if sp has availble time in the specific dates
WITH Serv AS
(
SELECT s.*
FROM Services s
INNER JOIN ServiceProvider sp ON sp.Id = s.ServiceProviderId
WHERE sp.CityId = @userCityId
AND s.Name LIKE @serviceName
),
StaffServices AS
(
SELECT s.*
FROM StaffMembers s
INNER JOIN StaffMemberService sms ON sms.StaffMemberId = s.Id
INNER JOIN Serv ON sms.ServiceId = Serv.Id
),
StaffMemberAppointment AS
(
SELECT ad.StaffMemberId, ad.Id, ad.Duration,a.ServiceProviderId
FROM AppointmentDetails ad
INNER JOIN Appointments a ON ad.AppointmentId = a.Id
INNER JOIN ServiceProvider sp ON sp.Id = a.ServiceProviderId
INNER JOIN StaffMemberService sms ON sms.StaffMemberId = ad.StaffMemberId
INNER JOIN Serv ON Serv.Id = sms.ServiceId
WHERE a.StartDt BETWEEN @startDate AND @endDate
),
appointmentParts AS
(
SELECT
sa.StaffMemberId, sa.ServiceProviderId,
SUM(Datepart(minute, sa.duration) + DATEPART(hour, sa.duration) * 60 ) /15 AS appointmentsparts
FROM
StaffMemberAppointment sa
GROUP BY
sa.StaffMemberId, sa.ServiceProviderId
)
SELECT
sm.*,
ap.appointmentsparts
FROM
StaffMembers sm
INNER JOIN
StaffServices ss ON ss.Id = sm.Id
LEFT JOIN
appointmentParts ap ON sm.Id = ap.StaffMemberId
我想要查找服务名称(如提供的名称)的基本思想,然后试图查找谁可以提供服务,并检查在特定日期范围内已预定的预约时间量然后找到包含服务的服务提供商。
IO统计信息a
(5 row(s) affected)
Table 'Appointments'. Scan count 0, logical reads 12, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table 'AppointmentDetails'. Scan count 5, logical reads 16, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table 'ServiceProvider'. Scan count 0, logical reads 20, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table 'StaffMemberService'. Scan count 3, logical reads 28, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table 'Services'. Scan count 6, logical reads 18, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
Table 'StaffMembers'. Scan count 0, logical reads 10, physical reads 0, read-ahead reads 0, lob logical reads 0, lob physical reads 0, lob read-ahead reads 0.
(1 row(s) affected)
时隙是1 15分钟。所以30分钟的约会是2个时隙。 我找不到一种简化此查询的方法,任何人都可以帮忙。
答案 0 :(得分:0)
如果您删除CTE并使用带有OUTER APPLY的单级联接来计算约会空位数量,您会得到什么样的执行计划?
SELECT sm.Id, sm.Name, sm.ServiceProviderId, sp.Name, appt.AppointmentSlots
FROM Services svc
INNER JOIN ServiceProvider sp ON sp.Id = svc.ServiceProviderId
INNER JOIN StaffMemberService sms ON sms.ServiceId = svc.Id
INNER JOIN StaffMembers sm ON sm.Id = sms.StaffMemberId
OUTER APPLY
(
SELECT SUM( Datepart(minute, ad.duration)
+ Datepart(hour, ad.duration)*60
) / 15 AS AppointmentSlots
FROM Appointments a INNER JOIN AppointmentDetails ad
ON ad.AppointmentId = a.Id
WHERE a.ServiceProviderId = sp.ID
AND ad.StaffMemberId = sms.StaffMemberId
AND a.StartDt between @startDate and @endDate
) appt
WHERE sp.CityId = @userCityId
AND svc.Name like @serviceName
AND ( AppointmentSlots < @maxSlots
OR AppointmentSlots IS NULL
)