Question

我想问一个有关将js文件导入另一个js文件并在gulp中使用它的问题。您可以看到我的gulp.config文件和gulpfile。当我尝试运行兽医的gulp任务时，我得到这样的错误;

[00:06:21] Using gulpfile ~\pluralsight-gulp-master\gulpfile.js
[00:06:21] Starting 'vet'...
[00:06:21] 'vet' errored after 13 ms
[00:06:21] Error: Invalid glob argument: undefined
    at Gulp.src (C:\Users\Altan\pluralsight-gulp-master\node_modules\vinyl-fs\li
b\src\index.js:20:11)

gulp.config.js

module.exports = function(){
    var config = {
        //all js to vet
        alljs: [
            './src/**/*.js',
            './*.js'
        ]
    };

    return config;
};


gulpfile.js
var gulp = require ('gulp');
var jscs = require ('gulp-jscs');
var jshint = require ('gulp-jshint');
var util = require ('gulp-util');
var gulpprint = require ('gulp-print').default;
var gulpif = require ('gulp-if');
var args = require ('yargs').argv;
var config= require('./gulp.config');

gulp.task('vet',done=>{

    gulp
    .src(config.alljs)
    .pipe(gulpif(args.verbose,gulpprint()))
    .pipe(gulpprint())
    .pipe(jscs())
    .pipe(jshint())
    .pipe(jshint.reporter('jshint-stylish',{verbose:true}));

    done();
});

Answer 1

您要从gulp.config.js返回一个函数

当您需要时，应该是

require('./gulp.config')()

gulp的可重用配置文件

1 个答案: