我实际上是从头开始创建一个论坛。当我们单击删除时,此脚本会创建一个弹出窗口,我将2个按钮删除,但只有一个工作。 代码:
HTML代码->
<!DOCTYPE html>
<html>
<head>
<title>Test</title>
<link rel="stylesheet" type="text/css" href="styletest.css">
</head>
<body>
<a href="#" id="remove_openpopup">remove</a>
<a href="#" id="remove_openpopup">remove2</a>
<div id="popup" class="popup">
<div class="popup_content">
<span class="close">×</span>
<p>Are you sure you wan't delete this categorie ?</p>
<button class="button_popup close_button">No</button>
<button class="button_popup close_button" onclick='document.getElementById("remove").submit()'>Yes</button>
</div>
</div>
</body>
</html>
JS:
var modal = document.getElementById("popup");
var btn = document.getElementById("remove_openpopup");
var span = document.getElementsByClassName("close")[0];
var span2 = document.getElementsByClassName("close_button")[0];
btn.onclick = function() {
modal.style.display = "block";
}
span.onclick = function() {
modal.style.display = "none";
}
span2.onclick = function() {
modal.style.display = "none";
}
window.onclick = function(event) {
if (event.target == modal) {
modal.style.display = "none";
}
}
我该怎么做:当我单击“删除”时,它会打开我的弹出窗口,但同时也会删除“ remove2”? 你能帮我吗 ? :)
答案 0 :(得分:1)
只是一个示例:)
在HTML中,我将id="remove_openpopup"
更改为class="remove_openpopup"
<a href="#" class="remove_openpopup">remove</a>
<a href="#" class="remove_openpopup">remove2</a>
在<script>
中,我将执行以下操作。
<script>
var modal = document.getElementById("popup");
var btns = Array.prototype.slice.call(document.querySelectorAll(".remove_openpopup"));
var span = document.getElementsByClassName("close")[0];
var span2 = document.getElementsByClassName("close_button")[0];
btns.forEach(function(btn) {
btn.onclick = function() {
modal.style.display = "block";
}
});
span.onclick = function() {
modal.style.display = "none";
}
span2.onclick = function() {
modal.style.display = "none";
}
window.onclick = function(event) {
if (event.target == modal) {
modal.style.display = "none";
}
}
</script>