Question

我想通过单击按钮在单个HTML页面中执行2个以上的操作。在菜单栏中有5个选项。即，当我单击“主页”时，它将执行某些操作，而当我单击“配置文件”时，它将执行特定操作。我为每个操作编写了单独的函数。如何对单个页面执行多种功能。

views.py

def home(request):
    return render(request, 'index.html', {})


def profile(request):
    if request.method == 'POST':
        form = ProfileForm(request.POST)
        if form.is_valid():
            first_name = request.session['username']
            print(first_name)
            test = Profile.objects.filter(first_name=first_name).values()
            for i in test:
                dict1 = i
                return render(request, 'index.html',
                              {'first_name': first_name, 'last_name': dict1['last_name'],
                               'phone_number': dict1['phone_number'], 'email': dict1['email'],
                               'address': dict1['address'], 'image': dict1['image']})
    else:
        form = ProfileForm()
        return render(request, 'profile.html', {'form': form})

def friends(request):
    friends_obj = Friends.objects.all()
    return render(request, 'index.html', {'friends_obj': friends_obj})

urls.py

urlpatterns = [
    path('home/', views.home, name="home"),
    path('profile/', views.profile, name="profile"),
    path('friends/', views.friends, name="friends"),
]

menu bar look like this我想通过单击菜单选项来执行所有操作。

Answer 1

def friends(request):和def home(request):使用Get方法，而def profile(request):使用Post方法。因此，第一步我们可以使用if request.method == "POST"为它们添加锯齿。对于使用相同方法的单独进程，我们需要在发送到django view之前，从前端（HTML-javascript等）的进程中附加一些标志，如下所示： template.html：

<form action="/navbar_aggregation" method="get">
  <input type="text" name="type" value="friends" hidden> 
  <!-- other input tag will be here as you need--> 
  <input type="submit" value="Submit">
</form>

然后您可以访问以这种方式输入视图。 view.py：

def navbar_aggregation(request):
    type = request.get.Get("type")  # name of hidden input 
    if (type == "friends"):
        # do same thing like 'def freinds(request)'
    elif(type == "family"):
        # do process for family form
    else :
        # do process for 'def home(request)'

所以现在我们知道如何分隔method =“ Get”或method =“ POST”。因此您的视图将如下所示：

view.py：

def navbar_aggregation(request):
   if request.method == "POST":
         form = ProfileForm(request.POST)
         if form.is_valid():
            first_name = request.session['username']
            print(first_name)
            test = Profile.objects.filter(first_name=first_name).values()
            for i in test:
                dict1 = i
                return render(request, 'index.html',
                              {'first_name': first_name, 'last_name': dict1['last_name'],
                               'phone_number': dict1['phone_number'], 'email': 
                                  dict1['email'],
                               'address': dict1['address'], 'image': dict1['image']})       
   else : # we are in method="GET"
      type = request.get.Get("type")  # name of hidden input 
      if(type == "friends"):
              friends_obj = Friends.objects.all()
              return render(request, 'index.html', {'friends_obj': friends_obj})
      elif(type == "form"):
            form = ProfileForm()
            return render(request, 'profile.html', {'form': form})
      elif(type == "foo"):
            # do something for foo's form 
            return something
      else:  # for sure it should be home's request because haven't any tag for "type"
         return render(request, 'index.html', {})

亲爱的朋友，我也是django的新手，所以我认为我的答案代码中有一些bug，但也许会对您有所帮助。我回答了您的问题，因为我没有看到任何专业开发人员没有回答您的问题。

如何通过单击按钮执行特定操作

1 个答案: