Question

使用DB2 for z / OS 10，我在一个表中有一列（ADDRESS3），该表在一个列中包含城市，州和邮政编码。但是，格式有些“自由格式”。（请参见下面的代码）

我可以通过逗号前的所有内容来成功解析城市。仅使用DB2 SQL，如何解析状态和邮政编码？

 $(".month").click(function() {
     var click = $(this);
     var month = click.val();
     var year = $("#years").val();

     $.ajax({
         url: "{{ path('av_platform_saisie') }}",
         type: 'POST',
         data: { 'month': month, 
                 'year': year
               },
         success: function (data) {
             alert('OK');
         },
         error : function(jqXHR, textStatus, errorThrown){}
     });
});

最终，我希望查询结果看起来像这样：

SELECT ADDRESS3,
       TRIM(SUBSTR(ADDRESS3,1,LOCATE(',', ADDRESS3)-1)) AS CITY
  FROM MYTABLE

ADDRESS3                            CITY         
----------------------------------  -------------
GRANADA HILLS       ,CA 91344       GRANADA HILLS
SIMI VALLEY         ,CA 93065       SIMI VALLEY  
BUENA PARK          ,CA 90621       BUENA PARK   
SHERMAN OAKS        ,CA 91423       SHERMAN OAKS 
GLENDALE            ,CA 91203-2089  GLENDALE     
VENTURA             ,CA 93002       VENTURA      
HAWTHORNE           ,CA 90250       HAWTHORNE    
PASADENA            ,CA 91185-2594  PASADENA     
BEVERLY HILLS       ,CA 90211       BEVERLY HILLS
ARCADIA             ,CA 91007       ARCADIA      
WALNUT CREEK        ,CA 94596       WALNUT CREEK 
INDEPENDANCE        ,CA 93526       INDEPENDANCE 
LOS ANGELES         ,CA 90017       LOS ANGELES

谢谢！

Answer 1

根据您的代码，如果状态为2个字符，而邮政编码为5个字符：

SELECT 
  ADDRESS3,
  TRIM(SUBSTR(ADDRESS3, 1, LOCATE(',', ADDRESS3)-1)) AS CITY,
  TRIM(SUBSTR(ADDRESS3, LOCATE(',', ADDRESS3) + 1), 2) AS STATE,
  TRIM(SUBSTR(ADDRESS3, LOCATE(',', ADDRESS3) + 4), 5) AS ZIP
FROM MYTABLE

Answer 2

我认为您需要假设格式始终相同。

  SELECT 
       TRIM(
         SUBSTR(
           SUBSTR(MYTABLE.A, LOCATE(',', MYTABLE.A) + 1)
           , 1
           , POSITION(' ' , SUBSTR(MYTABLE.A, LOCATE(',', MYTABLE.A) + 1))
         )
       ) AS STATE
    ,  TRIM(
           SUBSTR(
             SUBSTR(MYTABLE.A, LOCATE(',', MYTABLE.A) + 1)
           , POSITION(' ' , SUBSTR(MYTABLE.A, LOCATE(',', MYTABLE.A) + 1))
         ) 
       ) AS ZIP
  FROM MYTABLE

将演示结果转换为具有这些值的结果

测试数据

  VALUES
    ('GRANADA HILLS       ,CA 91344')
  , ('SIMI VALLEY         ,CA 93065') 
  , ('GLENDALE            ,CA 91203-2089')
  , ('SIMI VALLEY         ,CA    93065')  
  , ('SIMI VALLEY         ,CA    93065') 
  , ('GLENDALE            ,CA    91203-2089')

结果

STATE   ZIP
CA      91344
CA      93065
CA      91203-2089
CA      93065
CA      93065
CA      91203-2089

请参阅demo

Answer 3

有趣的是，这也起作用。

SELECT TRIM(SUBSTR(ADDRESS3, 1, locate(',', ADDRESS3) - 1)) AS city,
       SUBSTR(TRIM(SUBSTR(ADDRESS3, locate(',', ADDRESS3) + 1)), 1, 2) state,
       SUBSTR(TRIM(SUBSTR(TRIM(SUBSTR(ADDRESS3, locate(',', ADDRESS3) + 1)), 3)), 1, 5) zip
  FROM MyTable

使用DB2 SQL将1列解析为3列

3 个答案: