这是我上一篇文章的延续:here
我有这个查询:
SELECT INVOICE_NUMBER, INVOICE_SEQ_NUMBER, FILE_NUMBER
FROM (SELECT A.INVOICE_NUMBER, A.INVOICE_SEQ_NUMBER, B.FILE_NUMBER,
DENSE_RANK() OVER (ORDER BY A.INVOICE_NUMBER) as seqnum
FROM TABLE1 A JOIN
TABLE2 B
ON A.INVOICE_NUMBER = B.INVOICE_NUMBER AND
A.INVOICE_SEQ_NUMBER = B.INVOICE_SEQ_NUMBER
) t
WHERE seqnum <= 3;
结果如下:
-----------------------------------------------------
| INVOICE_NUMBER | INVOICE_SEQ_NUMBER | FILE_NUMBER |
------------------------------------------------------
|1111111111-1 | 1 | P4324324525 |
-----------------------------------------------------
|1111111111-1 | 2 | P4565674574 |
-----------------------------------------------------
|1111111111-1 | 3 | V4324552557 |
-----------------------------------------------------
|1111111111-1 | 4 | V4324552525 |
-----------------------------------------------------
|2222222222-2 | 1 | S4563636574 |
-----------------------------------------------------
|3333333333-3 | 1 | Q4324325675 |
-----------------------------------------------------
|3333333333-3 | 2 | Q4565674574 |
-----------------------------------------------------
因此,新的要求是如何获取相同发票编号的最大发票序列号?结果应该是这样的:
------------------------------------------------------------------------
| INVOICE_NUMBER | INVOICE_SEQ_NUMBER | FILE_NUMBER |MAX_INV_SEQ_NUMBER|
------------------------------------------------------------------------
|1111111111-1 | 1 | P4324324525 | 4 |
------------------------------------------------------------------------
|1111111111-1 | 2 | P4565674574 | 4 |
------------------------------------------------------------------------
|1111111111-1 | 3 | V4324552557 | 4 |
------------------------------------------------------------------------
|1111111111-1 | 4 | V4324552525 | 4 |
------------------------------------------------------------------------
|2222222222-2 | 1 | S4563636574 | 1 |
------------------------------------------------------------------------
|3333333333-3 | 1 | Q4324325675 | 2 |
------------------------------------------------------------------------
|3333333333-3 | 2 | Q4565674574 | 2 |
------------------------------------------------------------------------
答案 0 :(得分:0)
在选择部分中添加一个额外的列,如下所示-
SELECT
INVOICE_NUMBER,
INVOICE_SEQ_NUMBER,
FILE_NUMBER,
(
SELECT COUNT(*)
FROM TABLE1 A
JOIN TABLE2 B
ON A.INVOICE_NUMBER = B.INVOICE_NUMBER
AND A.INVOICE_SEQ_NUMBER = B.INVOICE_SEQ_NUMBER
AND A.INVOICE_NUMBER = t.INVOICE_NUMBER
)MAX_INV_SEQ_NUMBER
FROM ........
答案 1 :(得分:0)
SELECT INVOICE_NUMBER, INVOICE_SEQ_NUMBER, FILE_NUMBER, MAX(INVOICE_SEQ_NUMBER) OVER (PARTITION BY INVOICE_NUMBER)
FROM (SELECT A.INVOICE_NUMBER, A.INVOICE_SEQ_NUMBER, B.FILE_NUMBER,
DENSE_RANK() OVER (ORDER BY A.INVOICE_NUMBER) as seqnum
FROM TABLE1 A JOIN
TABLE2 B
ON A.INVOICE_NUMBER = B.INVOICE_NUMBER AND
A.INVOICE_SEQ_NUMBER = B.INVOICE_SEQ_NUMBER
) t
WHERE seqnum <= 3;
本质上,您只需要在select语句中使用它即可
MAX(INVOICE_SEQ_NUMBER) OVER (PARTITION BY INVOICE_NUMBER)
答案 2 :(得分:0)
将以下表达式添加到select
列表中:
, max(INVOICE_SEQ_NUMBER) over (partition by INVOICE_NUMBER) as MAX_INV_SEQ_NUMBER
。