我检查过,我没有发现错误:
$_SESSION['variable'] = 2
$preparado[1] = "Miguel";
$preparado[2] = "Carlos";
$segundo[1]= "Beltran";
$segundo[2] = "Sanz";
for($i = 1; $i <=$_SESSION['variable']; $i++){
$listo[$i] = $preparado1[$i] . $segundo[1];
}
for($i = ($_SESSION['variable'] + 1) ; $i <= ($_SESSION['variable'] * 2); $i++){
for($n = 1; $n <=$_SESSION['variable']; $n++){
$listo[$i] = $preparado1[$n] . $segundo[2];
}
}
for($i = 1;$i <=$_SESSION['variable'] * $_SESSION['extension']; $i++ ){
echo $final[$i] . "</br>";
}
我记得这个:
MiguelBeltran
CarlosBeltran
CarlosSanz
CarlosSanz
但我应该重申:
MiguelBeltran
CarlosBeltran
MiguelSanz
CarlosSanz
谢谢!
答案 0 :(得分:3)
我猜你有意
$preparado[0] = "Miguel"; // rather than [1]
$preparado[1] = "Carlos";
答案 1 :(得分:1)
您发布的代码与您提供的输出不一致:
您的输出中无法获得Miguel
:
$preparado[1] = "Miguel";
$preparado[1] = "Carlos";
因此,您指定Miguel
的唯一变量将覆盖下一行。
没有变量$preparado1
。
您应该发布实际用于生成输出的代码。
答案 2 :(得分:1)
假设:
$_SESSION['variable'] = 2
$preparado[1] = "Miguel";
$preparado[2] = "Carlos";
$segundo[1]= "Beltran";
$segundo[2] = "Sanz";
使用:
for ($i = 1; $i <= $_SESSION['variable']; ++$i) {
for ($j = 1; $j <= $_SESSION['variable']; ++$j) {
$listo[] = $preparado[$j].$segundo[$i];
}
}
答案 3 :(得分:0)
$preparado[1] = "Miguel";
$preparado[1] = "Carlos";
$segundo[1]= "Beltran";
$segundo[2] = "Sanz";
您已分配$preparado[1]
两次。