Question

这是我的情景...... 多个项目类型具有多个价格的多个项目。想要选择所有类型显示MAX价格的商品。无法弄清楚如何获得最大值？

输入：

ProductId   ProductType Description     Price

1 A BAKED BEANS 1.29

1 B BAKED BEANS 1.98

输出：

ProductId   ProductType Description     Price

1 A BAKED BEANS 1.98

1 B BAKED BEANS 1.98

有什么建议吗？

Answer 1

试试这个：

SELECT ProductId, 
    ProductType,
    Description,
    b.price
  FROM <YOUR_TABLE> a, 
        (SELECT MAX(price) price FROM <YOUR_TABLE>) b

对于那些喜欢ANSI语法的人：

SELECT ProductId, 
    ProductType,
    Description,
    b.price
  FROM <YOUR_TABLE> a INNER JOIN 
    (SELECT MAX(price) price FROM <YOUR_TABLE>) b
   ON 1=1

Answer 2

Select ProductId, ProductType, Description, MaxByDesc.MaxPrice
From Product
    Join    (
            Select Description, Max(Price) As MaxPrice
            From Product 
            Group By Description
            ) As MaxByDesc
        On MaxByDesc.Description = Product.Description

如果您使用的是SQL Server 2005或更高版本：

Select ProductId, ProductType, Description
    , Max( Price ) Over ( Partition By Description ) As MaxPrice
From Product

Answer 3

托马斯，对，除了你需要按类型分组：

Select ProductId, ProductType, Description, MaxByDesc.MaxPrice
From Product
Join    (
        Select Description, Max(Price) As MaxPrice
        From Product 
        Group By ProductType
        ) As MaxByDesc
    On MaxByDesc.ProductType = Product.ProductType

Answer 4

另一种方式：

SELECT ProductId
     , ProductType
     , Description
     , ( SELECT MAX(price)
         FROM Product pg
         WHERE pg.Description = p.Description 
       ) AS MaxPrice
  FROM Product p

SQL查询获取列的最大值并显示每一行

4 个答案: