我可以在组中获取排序后的数据,最后取出DolphinDB中的第一个N。
但是如何对mysql中的第一个N进行分组,排序和取出?
首先谢谢你。
DolphinDB代码如下:
sym = `C`MS`MS`MS`IBM`IBM`C`C`C$symbol;
price= 49.6 29.46 29.52 30.02 174.97 175.23 50.76 50.32 51.29;
qty = 2200 1900 2100 3200 6800 5400 1300 2500 8800;
timestamp = [09:34:07,09:36:42,09:36:51,09:36:59,09:32:47,09:35:26,09:34:16,09:34:26,09:38:12];
t1 = table(timestamp, sym, qty, price);
select top 2 * from t1 context by sym csort timestamp;
timestamp sym qty price
--------- --- ---- ------
09:34:07 C 2200 49.6
09:34:16 C 1300 50.76
09:32:47 IBM 6800 174.97
09:35:26 IBM 5400 175.23
09:36:42 MS 1900 29.46
09:36:51 MS 2100 29.52
答案 0 :(得分:1)
如果您有支持ROW_NUMBER()
的MySQLv8.0,则可以使用以下方式:
SELECT `timestamp`,sym,qty,price
FROM
(
SELECT
`timestamp`,sym,qty,price,ROW_NUMBER() OVER (PARTITION BY sym ORDER BY timestamp ASC) AS ranking
FROM `table`
) t
WHERE ranking<3
答案 1 :(得分:0)
SELECT sym, sum(qty) FROM table_name GROUP BY sym ORDER BY qty LIMIT 5;
哪里
GROUP BY
列-对行进行分组
ORDER BY
列-订购行
LIMIT
号-选择第一个行数