我有一个对象 lengthOfStay ,在其中尝试将其中的值连接起来并放在 customerApplication.lengthOfStay
上lengthOfStay:{
yrs: '',
mos:''
},
customerApplication: {
length_of_stay: this.lengthOfStayYrsMos
}
computed: {
lengthOfStayYrsMos(){
return this.customerApplication.length_of_stay =
Object.keys(this.lengthOfStay).map(k => this.lengthOfStay[k]).join(" ")
}
}
所以对于串联来说看起来不错,例如,结果是
lengthOfStay:{
yrs: '2',
mos:'2'
},
//result
customerApplication: {
length_of_stay: "2 2"
}
如何在其上连接字符串?这样结果就是
customerApplication: {
length_of_stay: "2 Yrs. & 2 Mos."
}
答案 0 :(得分:2)
您可以使用Object.entries()
从对象中获取键和值,然后将第一个字符更改为大写并以所需的格式连接
let data ={ lengthOfStay:{ yrs: '2', mos:'2' }}
let capFirstChar = (str)=> str[0].toUpperCase() + str.substr(1,)
let op = Object.entries(data.lengthOfStay)
.map(([key, value]) => `${value} ${capFirstChar(key)}.`)
.join(' & ')
console.log(op)
答案 1 :(得分:2)
尝试一下:
Object.keys(this.lengthOfStay).map(k => {
return `${this.lengthOfStay[k]} ${k}.`
}).join(" & ")
第一个大写字母
Object.keys(this.lengthOfStay).map(k => {
return `${this.lengthOfStay[k]} ${k.charAt(0).toUpperCase() + k.slice(1)}.`
}).join(" & ")