Question

我正在执行以下程序，在其中创建各种过程，就像它们是二叉树一样，我希望“左边”的孩子与“右边”的孩子做不同的事情，但它向我输出了两个孩子在右边或左边有2个孩子，我不想要那个。

void slice(int dir){
    if (dir == 1) {
        printf("izq ");
        printf("child pid %d   parent pid %d\n",getpid(),getppid());fflush(stdout);
    }
    else if (dir == 2){
        printf("der ");
        printf("child pid %d   parent pid %d\n",getpid(),getppid());fflush(stdout);
    }
}

void vector(int vector[], int length, int niveles){
    for(int i=1;i<=niveles;i++)
    {
    int error = 0;
pid_t child_pid[2] = { -1, -1 };
for (int dir=0; dir<=1; ++dir) {
    child_pid[dir] = fork();
    if (child_pid[dir] == -1) {
        error = 1;
        perror("fork");
    }

    if (child_pid[dir] == 0) { 
       // Here is where you place the code the child should execute.
       slice(dir);
       exit(0);
    }
}

for (int dir=0; dir<=1; ++dir) {
    if (child_pid[dir] == -1)
       continue;

    int status;
    pid_t pid = waitpid(child_pid[dir], &status, 0);
    if (pid == -1) {
        error = 1;
        perror("waitpid");
    }
    else if (WIFSIGNALED(status)) {
        error = 1;
        fprintf(stderr, "Child was killed by signal %d\n", WTERMSIG(status));
    }
    else if (WEXITSTATUS(status) != 0) {
        error = 1;
        fprintf(stderr, "Child exited with error %d\n", WEXITSTATUS(status));
    }
}

if (error)
   exit(1);
   } 
}

我的目标是为“ izq”调用一个函数，该函数在保持整个二叉树概念的同时，与“ der”有所不同。

Answer 1

请记住，父级和子级都从<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous"> <div class="projects"> <h1 id="project" class="pro">Projects</h1> <div class="flex-container"> <div class="container-fluid p-0 d-flex justify-content-center d-inline align-content-center"> <div class="row "> <div class="col-6 col-sm-2" > <div class="one" style="width: 285px; height: 275px;"> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front"> <img class="light" src="light.png"> </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div> </div> </div> </div> <div class="two"style="width: 299px; height: 275px;"> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front t2"> <img class="light" src="light.png"> </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div> </div> </div></div> <div class="three "style="width:285px; height:275px; "> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front t3"> <img class="light" src="light.png"> </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div> </div> </div></div> <div class="container-fluid p-0 d-flex align-content-center justify-content-center d-inline "> <div class="row "> <div class="col-6 col-sm-2" > <div class="four"style="width: 285px; height:275px;"> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front t4"> <img class="light" src="light.png"> </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div> </div> </div></div> <div class="five"style="width: 299px; height:275px;"> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front t5"> <img class="light" src="light.png" > </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div> </div></div></div> <div class="six"style="width: 285px; height:275px;"> <div class="flip-card"> <div class="flip-card-inner"> <div class="flip-card-front t6 "> <img class="light" src="light.png"> </div> <div class="flip-card-back"> <h1>John Doe</h1> <p>Architect & Engineer</p> <p>We love that guy</p> </div> </div></div></div></div></div> </div>开始执行，因此您需要执行以下操作：

select phone_number from table1;

result
1234567880

desired result
+11234567880

使过程像二叉树，并使每个孩子做不同的事情

1 个答案: