Question

我正在为c ++类编写一个接受文件指针的python绑定-

test <- data.table(col1 = c("cow, pig, horse"), col2 = c("fish, aardvark, moose"))
test2 <- data.table(col1 = c("orange, pig, frog"), col2 = c("whale, aardvark, elk"))
test <- rbind(test, test2)
cols <- c("col1", "col2")

test[, (cols) := (lapply(.SD, function(x) {
  paste(sort(trimws(strsplit(x, ',')[[1]])), collapse=',')
  })), .SDcols = cols]

我正在这样调用c ++函数-

  PYBIND11_MODULE(pywrapper, m) { 
...
 py::class_<Dog, Animal>(m, "Dog")
        .def(py::init<FILE * const>());

}

我收到了预期的错误-

f = open("test.log","w")

c = Dog(f)

如何在此处编写构造函数的包装？

Answer 1

我相信pybind11中没有实现 input 缓冲区。这是 output 缓冲区https://github.com/pybind/pybind11/blob/master/include/pybind11/iostream.h#L24

的实现

以下是使用缓冲区作为 output 流的示例：

.def("read_from_file_like_object",
   [](MyClass&, py::object fileHandle) {

     if (!(py::hasattr(fileHandle,"write") &&
         py::hasattr(fileHandle,"flush") )){
       throw py::type_error("MyClass::read_from_file_like_object(file): incompatible function argument:  `file` must be a file-like object, but `"
                                +(std::string)(py::repr(fileHandle))+"` provided"
       );
     }
     py::detail::pythonbuf buf(fileHandle);
     std::ostream stream(&buf);
     //... use the stream 

   },
   py::arg("buf")
)

Pybind11 _IO_FILE的文件指针包装

1 个答案: