Question

目标是使用Javascript（原始语言）删除介于[quote] [/ quote]和[quote = something] [/ quote]之间的所有文本（包括首字母）（不区分大小写））。如果删除引号后还存在双精度空格，则最好也将其删除。我按如下方式尝试了此Javascript，即：

t.replace(/\[quote.*\](.*?)\[\/quote\]/gi,'')

，但是我没有得到正确的结果。正确的方法是什么？

var t='Starting [QUOTE]this should be ignored hello[/quote] it. This is not quote and [quote=frank]HELLO quotes[/quote] Marky Mark 84WD. Last [quote=irene]try.[/quote]';

console.log(t.replace(/\[quote.*\](.*?)\[\/quote\]/gi,''));

//Current result: Starting.
//Expected result: Starting it. This is not quote and Marky Mark 84WD. Last

var t='[Quote]this should be ignored hello[/quote]. This is not quote and [quote=frank]HELLO quote[/quote] Marky Mark 84WD.';

console.log(t.replace(/\[quote.*\](.*?)\[\/quote\]/gi,''));

//Current result: Marky Mark 84WD.
//Expected result: . This is not quote and Marky Mark 84WD.

Answer 1

您可以使用/\[(quote)[^\]]*](.*?)\[\/\1\]/gi进行过滤：

var t='Starting [QUOTE]this should be ignored hello[/quote] it. This is not quote and [quote=frank]HELLO quotes[/quote] Marky Mark 84WD. Last [quote=irene]try.[/quote]';

console.log(t.replace(/\[(quote)[^\]]*](.*?)\[\/\1\]/gi,''));

var t='[Quote]this should be ignored hello[/quote]. This is not quote and [quote=frank]HELLO quote[/quote] Marky Mark 84WD.';

console.log(t.replace(/\[(quote)[^\]]*](.*?)\[\/\1\]/gi,''));

从文本中删除bb_quotes（[quote ..] [/ quote]）的JavaScript

1 个答案: