似乎无法将我的数据读取为整数并打印出数据。加上在def read(afile)函数中count = aFile.gets的关闭流(IOError)。 该程序包括数组,文件和循环。该程序的目的是获取一个数字10,并将该数字写入文件,然后在每一行中从0到10递增。
# takes a number and writes that number to a file then on each line
# increments from zero to the number passed
def write(aFile, number)
# You might need to fix this next line:
aFile.puts("number")
index = 0
while (index < number)
aFile.puts(number.to_s)
index += 1
end
end
# Read the data from the file and print out each line
def read(aFile)
# Defensive programming:
count = aFile.gets
if (is_numeric(count))
count = count.to_i
else
count = 0
puts "Error: first line of file is not a number"
end
index = 0
while (count < index)
line = aFile.gets
puts "Line read: " + line
end
end
# Write data to a file then read it in and print it out
def main
aFile = File.new("mydata.txt", "w") # open for writing
if aFile # if nil this test will be false
write(aFile, 10)
else
puts "Unable to open file to write!"
end
if aFile
read(aFile)
end
aFile.close
end
# returns true if a string contains only digits
def is_numeric?(obj)
if /[^0-9]/.match(obj) == nil
true
end
false
end
main
答案 0 :(得分:0)
这是皮肤代码,可以轻松添加我删除的功能。
def write(a_file, number)
(1..number).each { |n| a_file.puts(n) }
end
def read(a_file)
a_file.each { |line| puts line }
end
def main
a_file = File.new("mydata.txt", "w")
if a_file
write(a_file, 10)
else
puts "Unable to open file to write!"
end
a_file.close
a_file = File.open("mydata.txt", "r")
if a_file
read(a_file)
end
a_file.close
end
main
我发现的主要错误:
aFile.puts(number.to_s)
,您应放置index
,它是递增变量(is_numeric(count))
缺少?
旁注:对变量使用Ruby表示法:a_file
很好,aFile
不好。
答案 1 :(得分:0)
如果要使代码正常工作,请更改:
aFile = File.new("mydata.txt", "w")
收件人:
aFile = File.new("mydata.txt", "r+")
您可以更改:
count = aFile.gets
if (is_numeric(count))
收件人:
count = aFile.gets.to_i
if (count.is_a?(Fixnum))
,然后摆脱is_numeric?(obj)
方法。
您也无需增加计数器,也可以解决该问题。