大家好,你今天好吗,我希望你还好 我有一个具有许多活动的应用程序:
我需要做的是每隔(x)分钟使一次activity3弹出窗口,例如,每2或3分钟使Activity3弹出窗口我该怎么做,并提前致谢。
公共类MainActivity扩展了活动{
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
//Remove notification bar
this.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN, WindowManager.LayoutParams.FLAG_FULLSCREEN);
//Remove title bar
this.requestWindowFeature(Window.FEATURE_NO_TITLE);
//load the xml file for the starting loading screen
setContentView(R.layout.activity_main);
Log.d("MainActivity:", "onCreate: created activity_main.xml UI succesfully.");
new Timer().schedule(new TimerTask(){
public void run() {
startActivity(new Intent(MainActivity.this, PrimaryActivity.class));
finish();
Log.d("MainActivity:", "onCreate: waiting 5 seconds for MainActivity... loading PrimaryActivity.class");
}
}, 5000 );
}
}
在发布之前,我不知道如何尝试此操作,因此,谢谢您的帮助。
答案 0 :(得分:0)
'将弹出式函数设为静态,并使用类似的类名对其进行调用'
yourclassname.popupFunction(Context);
“在您要打开主要活动的创建方法中”
public static void popupFunction(Activity activity){
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
startActivity(new Intent(activity, PrimaryActivity.class));
finish();
Log.d("MainActivity:", "onCreate: waiting 5 seconds for MainActivity...
loading PrimaryActivity.class");
}
},5000);
}
“希望您能得到答案谢谢”