Question

如何通过LINQ使用DATETIME2列在C＃中工作并获得微秒分辨率？现在，即使服务器数据类型设置为DATETIME2，我的LINQ对象也有一个DateTime字段，它似乎不会处理微秒。

Answer 1

即使DATETIME2处理微秒，.NET 4也不会。如果您需要专门处理微秒，则可以在SQL Server中使用过程而无需通过应用程序读取值。

.NET参考说：

价值的小数部分是小部分毫秒。对于例如，4.5相当于4 毫秒和5000个刻度，其中一个毫秒= 10000滴答。

string dateFormat = "MM/dd/yyyy hh:mm:ss.fffffff"; 
DateTime date1 = new DateTime(2010, 9, 8, 16, 0, 0);
Console.WriteLine("Original date: {0} ({1:N0} ticks)\n",
                  date1.ToString(dateFormat), date1.Ticks);

DateTime date2 = date1.AddMilliseconds(1);
Console.WriteLine("Second date:   {0} ({1:N0} ticks)",
                  date2.ToString(dateFormat), date2.Ticks);
Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)\n",
                  date2 - date1, date2.Ticks - date1.Ticks);                        

DateTime date3 = date1.AddMilliseconds(1.5);
Console.WriteLine("Third date:    {0} ({1:N0} ticks)",
                  date3.ToString(dateFormat), date3.Ticks);
Console.WriteLine("Difference between dates: {0} ({1:N0} ticks)",
                  date3 - date1, date3.Ticks - date1.Ticks);                        
// The example displays the following output:
//    Original date: 09/08/2010 04:00:00.0000000 (634,195,584,000,000,000 ticks)
//    
//    Second date:   09/08/2010 04:00:00.0010000 (634,195,584,000,010,000 ticks)
//    Difference between dates: 00:00:00.0010000 (10,000 ticks)
//    
//    Third date:    09/08/2010 04:00:00.0020000 (634,195,584,000,020,000 ticks)
//    Difference between dates: 00:00:00.0020000 (20,000 ticks)

参考：DateTime.AddMilliseconds Method

C＃SQL Server 2008 DATETIME2列

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