我只想取出数据框列中包含类似数据的日期部分
$83,00010/7/2016 10/7/2016 # is the date here
$721,0002/7/2015 2/7/2015 # is the date here
$3,00012/12/2015 12/12/2015 # is the date here
我尝试过类似的模式
^(?!,\d{3}) and (\$[,\d{3}]*\,\d{3})
但是我不能完全选择日期部分。
答案 0 :(得分:1)
这有点复杂,让我们从一个简单的表达式开始,然后将其扩展。我希望我们的金钱部分有,
,然后我们可以尝试:
,\d{3}(\d{1,2}\/.+?\/\d{4})
或
([1-3]?\d\/.+?\/\d{4})
# coding=utf8
# the above tag defines encoding for this document and is for Python 2.x compatibility
import re
regex = r"([1-3]?\d\/.+?\/\d{4})"
test_str = ("$83,00010/7/2016 ----> 10/7/2016 is the date here,\n"
"$721,0002/7/2015 ----> 2/7/2015 is the date here,\n"
"$3,00012/12/2015 -----> 12/12/2015 is the date here")
matches = re.finditer(regex, test_str, re.MULTILINE)
for matchNum, match in enumerate(matches, start=1):
print ("Match {matchNum} was found at {start}-{end}: {match}".format(matchNum = matchNum, start = match.start(), end = match.end(), match = match.group()))
for groupNum in range(0, len(match.groups())):
groupNum = groupNum + 1
print ("Group {groupNum} found at {start}-{end}: {group}".format(groupNum = groupNum, start = match.start(groupNum), end = match.end(groupNum), group = match.group(groupNum)))
# Note: for Python 2.7 compatibility, use ur"" to prefix the regex and u"" to prefix the test string and substitution.
jex.im可视化正则表达式:
答案 1 :(得分:0)
以下正则表达式将为您返回日期:
',\d{3}(\d{1,2}/\d{1,2}/\d{4})$'