Question

我正从视图控制器A导航到视图控制器B。

 @IBAction func companyListTapped(_ sender: Any) {
    let viewcontrollerB = Bundle.main.loadNibNamed(String(describing: ListViewController.self),
                                                      owner: self,
                                                      options: nil)?[0] as! viewcontrollerB

  self.navigationController?.pushViewController(viewcontrollerB, animated: true)
  }

现在，在导航时，我还想将模型和tableviewcell传递给ViewcontrollerB。为此，我做了一个泛型函数并像这样访问它...

功能是这个。.

func doSomething<M,T>(_ a: M.Type, myType: T.Type) {
    print(M.self)
    print(T.self)
  }

像这样访问...

@IBAction func companyListTapped(_ sender: Any) {
    let viewcontrollerB = Bundle.main.loadNibNamed(String(describing: ListViewController.self),
                                                      owner: self,
                                                      options: nil)?[0] as! ViewControllerB
    doSomething(Company.self, myType: CompanyCell.self) -> //Accessed here
  self.navigationController?.pushViewController(viewcontrollerB, animated: true)
  }

现在，打印M.self和T.self给我Company和CompanyCell，分别是我的模型和tableviewcell。但是我如何将这两个值（即Company和CompanyCell）传递给我无法弄清楚的视图控制器B。希望有人能帮忙...

Answer 1

在这种情况下，您不需要泛型。您只需要将值从源视图控制器 ListViewController传递给目标视图控制器 ViewControllerB

class ListViewController: UIViewController {

    @IBAction func companyListTapped(_ sender: Any) {

        let viewcontrollerB = Bundle.main.loadNibNamed(String(describing: ListViewController.self),
                                                       owner: self,
                                                       options: nil)?[0] as! ViewControllerB

        // Assuming you have companyObject and companyCellObject of type Company and CompanyCell respectively   
        viewcontrollerB.companyObject = companyObject // replace objects here
        viewcontrollerB.companyCellObject = companyCellObject // and here

        navigationController?.pushViewController(viewcontrollerB, animated: true)

    }

}

class ViewControllerB : UIViewController {

    // Assuming you have types with the same name
    var companyObject: Company?
    var companyCellObject: CompanyCell?

}

无法从泛型中获取价值

1 个答案: