Question

我有从登录名获得的Api密钥。如何使用该密钥向服务器发出http.get请求？

这是我的钥匙：

"access": "eyJ0eXAiOiJKV1QiLCJhbGciOiJIUzI1NiJ9.eyJ0b2tlbl90eXBlIjoiYWNjZXNzIiwiZXhwIjoxNTU5MTc3NDg4LCJqdGkiOiIxZGU5MzlkNTNiYWQ0NDM4OWZjOGQ5MDJmYmRkMzYzMyIsInVzZXJfaWQiOjF9.vQFnfQSeTgxeOav--H4a5nf2Rs0xMWyDRewp9kkZXks"

运动课：

class Exercise {
  final int id;
  final String name;

  Exercise(this.id, this.name);

  Exercise.fromJson(Map<String, dynamic> j)
  : id = j['id'],
    name = j['name'];
}

获取不带令牌的请求（无法正常工作，我需要一个解决方案）：

Future<List<Exercise>> _getExercises() async {
http.Response data = await http.get(
  'url:8000/api/database/exercises/');
List jsonData = json.decode(data.body);
List<Exercise> allExercises = jsonData.map<Exercise>((j) => Exercise.fromJson(j)).toList();
return allExercises;
}

Answer 1

您需要设置请求的标题

 Map<String, String> requestHeaders = {
       'Content-type': 'application/json',
       'Accept': 'application/json',
       'Authorization' : 'Bearer TOKENHERE'
     };

await http.get(
  'url:8000/api/database/exercises/',headers:userHeader)

但是我建议您尝试一下https://pub.dev/packages/dio 您只需将令牌提供给拦截器就很容易，然后它将为您添加令牌

var http = new Dio();

InterceptorsWrapper tokenInterceptor;

addTokenInterceptor(token) {
  // Add interceptor
  tokenInterceptor = InterceptorsWrapper(onRequest: (Options options) {
    options.headers['Authorization'] = "Bearer " + token;
  });
  http.interceptors.add(tokenInterceptor);
}

removeTokenInterceptor() {
  http.interceptors.remove(tokenInterceptor);
}

之后，只需使用http对象执行http服务

Answer 2

我认为您正试图在请求中传递您的访问令牌。您可以像这样在标头中传递令牌：

 http.get(url, headers: <String,String>{'access':token});

Flutter使用承载令牌（JWT）获取请求-Django后端

2 个答案: