Rebus Pub Sub:检索订户上的标头

时间:2019-05-29 21:09:03

标签: rebus rebus-azureservicebus

标题与Azure服务总线一起发布,如下所示:

 string content = "body";
 await _busPublisher.Activator.Bus.Publish(content, headers);

如何在订户上同时检索标头和内容?

class Handler :  IHandleMessages<string>
    {

    public Handler(IMessageContext messageContext, ILog log)
    {
        _messageContext = messageContext;
        _log = log;
    }

        public async Task Handle(string message)
        {
            Console.WriteLine("Handle(string message): {0}", message);

        }
    }

更新

以下是一种解决方案。这是最好的解决方案吗?

        public Handler(IMessageContext messageContext, ILog log)
    {
        _messageContext = messageContext;
        _log = log;
    }
            public async Task Handle(string message)
            {
                Console.WriteLine("Handle(string message): {0} ", message);
                Console.WriteLine("headers: {0} ", string.Join(' ', _messageContext.Headers));

            }

当像下面实例化处理程序时,可以使用依赖注入代替吗?

        var Activator = new BuiltinHandlerActivator();

        Activator.Register((mc) =>
            {
                return new Handler(mc, log);  //no new?

            }

1 个答案:

答案 0 :(得分:1)

接受的IMessageContext注入到处理程序的构造函数中是可行的方法:

public class Handler : IHandleMessages<string>
{
    readonly IMessageContext messageContext;

    public Handler(IMessageContext messageContext, ILog log)
    {
        this.messageContext = messageContext;
    }

    public async Task Handle(string message)
    {
        var headers = messageContext.Headers;

        // do stuff
    }
}

如果您使用的是BuiltinHandlerActivator,则可以像这样注入它:

activator.Register(context => new Handler(context));

或者如果您的处理程序中还需要IBus

activator.Register((bus, context) => new Handler(bus, context));