Question

目标：我想从串行监视器中输入一个整数。这些值稍后将用作delay（value）命令的一部分。延迟的目的是使两个振动电机稍微不同步。

问题：我正在尝试从命令行获取诸如60或400之类的值。当前值与输入值不匹配。

我的直觉说这是数据格式问题。我希望有人能帮助我理解为什么每个数字都打印为数字。

提示子例程代码：

  while (!Serial.available()) {       //this holds until we see a serial prompt
    } 
  if (Serial.available() > 0) {
    uint8_t inChar = Serial.read();
    Serial.println(inChar);
    // convert the incoming byte to a char and add it to the string:
    if (isDigit(inChar)) {
      receivedChar += (char)inChar;
    }

    // if you get a newline, print the string, then the string's value:
    if (inChar == '\n') {
      Serial.print("Delay Value:");
      Serial.println(receivedChar.toInt());
      Serial.print("String: ");
      Serial.println(receivedChar);
      // clear the string for new input:      
    }
    newData = true;
    prompthold = false;
  }
}

循环代码：

  void loop(){
    while (prompthold == false) {
      prompthold = true;

      Serial.println("Please enter delay");
      receivedChar = "";
      srl_prompt();
      apparentmotion();
    }

    delay(500);

  }

诊断信息：输入1234567890

返回：

16:28:13.079 -> 49
16:28:13.079 -> Please enter delay
16:28:13.079 -> 50
16:28:13.079 -> Please enter delay
16:28:13.079 -> 51
16:28:13.079 -> Please enter delay
16:28:13.079 -> 52
16:28:13.079 -> Please enter delay
16:28:13.079 -> 53
16:28:13.113 -> Please enter delay
16:28:13.113 -> 54
16:28:13.113 -> Please enter delay
16:28:13.113 -> 55
16:28:13.113 -> Please enter delay
16:28:13.113 -> 56
16:28:13.147 -> Please enter delay
16:28:13.147 -> 57
16:28:13.147 -> Please enter delay
16:28:13.147 -> 48
16:28:13.147 -> Please enter delay
16:28:13.147 -> 10
16:28:13.147 -> Delay Value:0
16:28:13.147 -> String: 
16:28:13.147 -> Please enter delay

输入200

16:29:06.082 -> Please enter delay
16:34:02.121 -> 50
16:34:02.121 -> Please enter delay
16:34:02.121 -> 48
16:34:02.155 -> Please enter delay
16:34:02.155 -> 48
16:34:02.155 -> Please enter delay
16:34:02.155 -> 10
16:34:02.155 -> Delay Value:0
16:34:02.155 -> String: 
16:34:02.155 -> Please enter delay

Answer 1

好的，我已经解决了。如果使用Serial.read（），则将获得字符串/ ASCII。如果使用Serial.parseInt（），则会获得一个值。更新的代码如下：

void srl_prompt() {
  while (!Serial.available()) {       //this holds until we see a serial prompt
    } 
  if (Serial.available() > 0) {
    uint8_t inChar = Serial.parseInt();
    Serial.println(inChar);
    // convert the incoming byte to a char and add it to the string:
    if (isDigit(inChar)) {
      receivedChar += (char)inChar;
    }

    // if you get a newline, print the string, then the string's value:
    if (inChar == '\n') {
      Serial.print("Delay Value:");
      Serial.println(receivedChar.toInt());
      Serial.print("String: ");
      Serial.println(receivedChar);
      // clear the string for new input:      
    }
    newData = true;
    prompthold = false;
  }
}

与串行监视器中的值不同的Serial.read返回值

1 个答案: