Question

我正在构建电子邮件验证脚本，并且我使用的是Ajax，因此每当用户填写虚假或无效的电子邮件时，都会显示带有错误名称的错误栏，并且当电子邮件为真且属于该电子邮件时如果是有效帐户，则会向用户发送一封带有说明的电子邮件，错误栏显示已发送电子邮件。问题是，即使邮件功能无法正常工作，错误栏也会一直显示已发送电子邮件。因此，我不会在错误栏中显示一些行来检测是否未发送电子邮件以显示“未发送电子邮件”。

这是我的php文件：

    <?php 

include '../../app/init.php';

        /* Clean email */
    $recover_email = $_POST['recover_email'];

       /* check if email is valid */
    if(!filter_var($recover_email, FILTER_VALIDATE_EMAIL)) {

        /* email not valid */
        echo 3;

        /* Check if email exist */
    } else if(Database::exists('user_id', 'users', ['email' => $recover_email])) {


        /* Define some variables */
        $user_id            = Database::simple_get('user_id', 'users', ['email' => $recover_email]);
        $lost_password_code = md5($recover_email + microtime());

        /* Update the current activation email */
        $database->query("UPDATE `users` SET `lost_password_code` = '{$lost_password_code}' WHERE `user_id` = {$user_id}");

        /* Send the email */
        sendmail($recover_email,  $settings->contact_email, $language->lost_password->email->title, sprintf($language->lost_password->email->content, $settings->url, $recover_email, $lost_password_code));

        /* email exist */
        echo true; 

    } else if(!Database::exists('user_id', 'users', ['email' => $email])) {

        /* email not exist */
        echo false;
    }

?>

这是我的邮件功能：

function send_mail($to, $from, $title, $message) {

    $headers = "From: " . strip_tags($from) . "\r\n";
    $headers .= "MIME-Version: 1.0\r\n";
    $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";

    mail($to, $title, $message, $headers);
}

function sendmail($to, $from, $title, $message) {
    global $settings;

    if(!empty($settings->smtp_host) && !empty($settings->smtp_port) && !empty($settings->smtp_user) && !empty($settings->smtp_pass)) {

        $mail = new PHPMailer;
        $mail->isSMTP();
        $mail->SMTPDebug = 0;
        $mail->SMTPSecure = 'tls';
        $mail->SMTPAuth = true;
        $mail->isHTML(true);

        $mail->Host = gethostbyname('tls://'.$settings->smtp_host);
        $mail->Port = $settings->smtp_port;
        $mail->Username = $settings->smtp_user;
        $mail->Password = $settings->smtp_pass;

        $mail->setFrom($from, $settings->title);
        $mail->addReplyTo($from, $settings->title);
        $mail->addAddress($to);
        $mail->Subject = $title;
        $mail->Body = $message;

        if (!$mail->send()) {
            send_mail($to, $from, $title, $message);
        }

    } else {
        send_mail($to, $from, $title, $message);
    }

}

我只需要在php文件上添加几行即可将其返回作为对ajax文件的响应

Answer 1

mail()如果成功接受了邮件发送，则返回TRUE，否则返回FALSE。因此，您需要运行if语句来检查邮件是否被接受发送。

<?php

function send_mail($to, $from, $title, $message)
{

    $headers = "From: " . strip_tags($from) . "\r\n";
    $headers .= "MIME-Version: 1.0\r\n";
    $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";

    if (mail($to, $title, $message, $headers)) {

        return true;
    } else {

        return false;
    }
}

function sendmail($to, $from, $title, $message)
{
    global $settings;

    if (!empty($settings->smtp_host) && !empty($settings->smtp_port) && !empty($settings->smtp_user) && !empty($settings->smtp_pass)) {

        $mail = new PHPMailer;
        $mail->isSMTP();
        $mail->SMTPDebug  = 0;
        $mail->SMTPSecure = 'tls';
        $mail->SMTPAuth   = true;
        $mail->isHTML(true);

        $mail->Host     = gethostbyname('tls://' . $settings->smtp_host);
        $mail->Port     = $settings->smtp_port;
        $mail->Username = $settings->smtp_user;
        $mail->Password = $settings->smtp_pass;

        $mail->setFrom($from, $settings->title);
        $mail->addReplyTo($from, $settings->title);
        $mail->addAddress($to);
        $mail->Subject = $title;
        $mail->Body    = $message;

        if (!$mail->send()) {
            if (!send_mail($to, $from, $title, $message)) {

                echo "Error sending email, please try again later";
            }
        }

    } else {
        if (!send_mail($to, $from, $title, $message)) {

            echo "Error sending email, please try again later";
        }
    }

}

Answer 2

只需在if条件中使用mail（），并在if和else块中打印适当的消息。它会解决问题

if(mail($to, $title, $message, $headers)){
//success message
}
else{
//error message
}

如果邮件功能不起作用，则会显示错误

2 个答案: