我有一个带有两个TextInputs的组件。在每个TextInput下,都有一个FlatList,当用户键入某些字符时会渲染该FlatList(实际的渲染发生在ListItem中,React-native元素中的模块)。对于第一个FlatList,一切正常-可以按预期呈现。问题出在第二个FlatList上-我无法渲染它。查看此gif以了解我的意思:https://gph.is/g/E1G1jnx
我已经尝试按照One of two FlatLists not rendering items in same component的建议使用“ extraData”道具,但是并不能解决问题。
我知道问题不在于onChangeAddress(address)是一个异步函数。我使用了静态数据集,但仍然无法渲染。
import { StyleSheet, Text, TextInput, View, FlatList, ImageBackground, Image } from 'react-native';
import { ListItem, Button } from 'react-native-elements';
class Home extends Component {
constructor(props) {
super(props);
this.state = {
jobInputValue: '',
addressInputValue: '',
showJobsDropdown: false,
showAddressesDropdown: false,
jobsList: this.props.jobTitles.results,
addressPredictions: []
};
}
async onChangeAddress(address) {
//fetch the data from the API
//filteredAddresses stores the data from the API
if (filteredAddresses.length > 0) {
this.setState({
addressPredictions: filteredAddresses,
showAddressesDropdown: true
})
}
}
}
render() {
return (
<ImageBackground style={styles.bkgImage} source={require('../assets/homepage_background.jpg')}>
<TextInput
style={styles.jobTextInput}
value={this.state.jobInputValue}
placeholder='Ce job cauți?'
onChangeText={(jobInputValue) => this.setState({jobInputValue}, this.checkJobsDropdown(jobInputValue))}/>
<FlatList
data={this.state.jobsList}
style={this.state.showJobsDropdown ? styles.jobsDropdownStyle : styles.dropdownHiddenStyle}
renderItem={({ item }) => (
<ListItem
title={item}
containerStyle={{paddingBottom: -4}}
titleProps={{ style: styles.dropdownItemStyle}}
onPress={() => this.setState({jobInputValue: item}, this.hideJobsDropdown())}
/>
)}
keyExtractor={item => item}
/>
<TextInput
style={styles.addressTextInput}
value={this.state.addressInputValue}
placeholder='La ce adresă locuiești?'
onChangeText={addressInputValue => this.onChangeAddress(addressInputValue)}
/>
//the issue is with the FlatList below
<FlatList
data={this.state.addressPredictions}
extraData={this.state}
style={this.state.showAddressesDropdown ? styles.addressDropdownStyle : styles.dropdownHiddenStyle}
renderItem={({ addressItem, index }) => (
<ListItem
title={addressItem}
containerStyle={{paddingBottom: -4}}
titleProps={{style: styles.dropdownItemStyle}}
onPress={() => this.setState({addressInputValue: addressItem}, this.hideAddressesDropdown())}
/>
)}
keyExtractor={(addressItem, index) => index.toString()}
/>
<Button
title="CAUTĂ"
type="outline"
underlayColor={colors.red}
titleStyle={styles.buttonTitleStyle}
color={colors.red}
style={styles.buttonStyle}
onPress={this.printState}
/>
</ImageBackground>
);
}
任何帮助将不胜感激!
答案 0 :(得分:1)
问题在于数据的结构化以呈现第二个平面列表的项目:
renderItem={({ addressItem, index }) => (
<ListItem
title={addressItem}
containerStyle={{paddingBottom: -4}}
titleProps={{style: styles.dropdownItemStyle}}
onPress={() => this.setState({addressInputValue: addressItem}, this.hideAddressesDropdown())}
/>
)}
({ addressItem, index })
<-这里没有addressItem
。您必须用item
替换它,因为Flatlist提供了一个{ item: Object, index: Number, separators: object }
结构的对象作为renderList回调的参数。