Question

我正在尝试删除旧的AWS快照，但是我需要排除任何描述值以“ Created by CreateImage”开头的快照。

我尝试了boto3.resource和boto3.client的变体。

from datetime import datetime, timedelta, timezone

import boto3
client = boto3.client('ec2')
snapshots = client.snapshots.filter(Description!='Created by CreateImage')

def lambda_handler(event, context):
    for snapshot in snapshots:
        start_time = snapshot.start_time
        delete_time = datetime.now(tz=timezone.utc) - timedelta(days=790)
        if delete_time > start_time:
            snapshot.delete()
            print('Snapshot with Id = {} is deleted '.format(snapshot.snapshot_id))

现在，我有大约10张超过790天的快照，其中5张快照的描述以“ CreateImage by CreateImage”开头，而5张快照没有。在测试时，我想删除没有说明的那些快照。

我得到的错误是：

模块初始化错误：“ EC2”对象没有属性“快照”

Answer 1

您需要使用describe_snapshots并正确传入过滤器。

此外，结果将是字典，而不是对Snapshot类的引用，因此您需要更新提取属性和删除快照的方式。

类似的东西：

from datetime import datetime, timedelta, timezone

import boto3
client = boto3.client('ec2')
snapshots = client.describe_snapshots(Filters=[
        {
            'Name': 'description',
            'Values': [
                'Created by CreateImage',
            ]
        },
    ])['Snapshots']

def lambda_handler(event, context):
    for snapshot in snapshots:
        start_time = snapshot['StartTime']
        delete_time = datetime.now(tz=timezone.utc) - timedelta(days=790)
        if delete_time > start_time:
            client.delete_snapshot(SnapshotId=snapshot['SnapshotId'])
            print('Snapshot with Id = {} is deleted '.format(snapshot['SnapshotId']))

参考： https://boto3.amazonaws.com/v1/documentation/api/latest/reference/services/ec2.html#EC2.Client.describe_snapshots

Answer 2

这是一个可行的版本。

请注意使用OwnerIds=['self']，它将结果限制为仅由您的AWS账户创建的快照。否则，它将返回任何AWS账户创建的所有公共可用快照。

from datetime import datetime, timedelta, timezone

import boto3

def lambda_handler(event, context):

    delete_time = datetime.now(tz=timezone.utc) - timedelta(days=790)

    ec2_resource = boto3.resource('ec2', region_name='ap-southeast-2')
    snapshots = ec2_resource.snapshots.filter(OwnerIds=['self'])

    for snapshot in snapshots:
        if not snapshot.description.startswith('Created by CreateImage') and delete_time > snapshot.start_time:
            snapshot.delete()
            print('Snapshot with Id = {} is deleted '.format(snapshot.snapshot_id))

删除快照（具有特定描述的快照除外）

2 个答案: