Question

我想提取May和JUNE中存在但JULY中不存在的那些帐户ID。我有6个月的数据

我尝试使用CONDITION（AND / NOT）

SELECT ACCOUNT_ID, DATA_MONTH
FROM DATA1
WHERE DATA_MONTH ='01-MAY-18' AND DATA_MONTH <> '01-JULY-18
GROUP BY DATA_MONTH

我仍然在7月的哪个位置获得帐户ID

Answer 1

您可以将所需的条件放在HAVING子句中：

SELECT ACCOUNT_ID
FROM DATA1
GROUP BY ACCOUNT_ID
HAVING
  SUM(CASE WHEN MONTH(DATA_MONTH) = 5 THEN 1 ELSE 0 END) > 0
  AND
  SUM(CASE WHEN MONTH(DATA_MONTH) = 6 THEN 1 ELSE 0 END) > 0
  AND
  SUM(CASE WHEN MONTH(DATA_MONTH) = 7 THEN 1 ELSE 0 END) = 0

我假设您的rdbms中有一个类似MONTH()的函数可以从日期中提取月份。
如果还要检查年份，则可以在每种情况下都进行检查，因此必须更改为：

CASE WHEN MONTH(DATA_MONTH) = 7 AND YEAR(DATA_MONTH) = 2018 THEN 1 ELSE 0

Answer 2

您的日期格式看起来像Oracle，因此我将为该数据库回答。

想法是使用条件聚合：

SELECT ACCOUNT_ID, DATA_MONTH
FROM DATA1
WHERE DATA_MONTH >= DATE '2018-05-01' AND
      DATA_MONTH < DATE '2018-08-01'
GROUP BY ACCOUNT_ID
HAVING COUNT(DISTINCT DATA_MONTH) = 2 AND
       MAX(DATA_MONTH) < DATE '2018-07-01';

这假设您的所有日期都在该月的第一天。

Answer 3

使用SQL Server的Month函数为您提供了一个解决此问题的易于理解的示例。

SELECT ACCOUNT_ID
FROM DATA1
WHERE MONTH(DATA_MONTH) in (5,6) AND YEAR(DATA_MONTH) = 2018 AND MONTH(DATA_MONTH) NOT IN (7) 
GROUP BY ACCOUNT_ID

Answer 4

SELECT ACCOUNT_ID, DATA_MONTH
FROM DATA1
WHERE MONTH(DATA_MONTH) =5 AND MONTH(DATA_MONTH) = 6
GROUP BY DATA_MONTH

Answer 5

SELECT ACCOUNT_ID, DATA_MONTH
FROM DATA1
WHERE MONTH(DATA_MONTH)  BETWEEN 5  AND  6
GROUP BY Year(DATA_MONTH),month(DATA_MONTH)

查询以查找指定月份的帐户

5 个答案: