Question

我有一个想要进行人力资源管理的项目在搜索为时显示评级和非评级求职者雇主。
I have tried this but this only gives jobseekers whose ratings has been set.

public function search(Request $request)
    {
        $query = $request->get('query');
        if (isset($query)) {
            $queryParam = explode(' ', $query);
        } else {
            $queryParam = null;
        }
        $jobseekers = JobSeekers::where(function ($que) use ($queryParam) {
            if (isset($queryParam)) {
                foreach ($queryParam as $queries) {
                    $que->orWhere('job_seekers.category', 'like', '%' . $queries . '%');
                    $que->orWhere('job_seekers.keywords', 'like', '%' . $queries . '%');
                    $que->orWhere('job_seekers.experience', 'like', '%' . $queries . '%');
                }
            }
        })->join('ratings', 'job_seekers.id', '=', 'ratings.js_id')
            ->groupBy('job_seekers.id')
            ->select('job_seekers.id', DB::raw('AVG( ratings.rating )  AS average_rating'))
            ->orderBy('average_rating', 'desc')
            ->get();
        return view('search.search_all', compact('jobseekers'));
    }

    I have a rating table .

    Schema::create('ratings', function (Blueprint $table) {
        $table->increments('id');
        $table->integer('emp_id')->unsigned();
        $table->integer('js_id')->unsigned();
        $table->integer('rating')->unsigned();
        $table->longText('description')->nullable();
        $table->foreign('emp_id')->references('id')->on('employers');
        $table->foreign('js_id')->references('id')->on('job_seekers');
        $table->timestamps();
    });

我只获得给出了评级的对象的数据，而没有得到数据，但没有评级。

Answer 1

尝试使用leftJoin()代替join()。

JOIN仅选择在联接表中具有数据的结果。

LEFT JOIN选择所有结果并从联接表中附加数据。

public function search(Request $request)
{
    $jobseekers = JobSeekers
        ::when($request->get('query'), function($query) use ($request) {
            $words = explode(' ', $request->get('query'));
            foreach($words as $word){
                $query->orWhere('job_seekers.category', 'like', '%' . $word . '%');
                $query->orWhere('job_seekers.keywords', 'like', '%' . $word . '%');
                $query->orWhere('job_seekers.experience', 'like', '%' . $word . '%');
            }
        })
        ->leftJoin('ratings', 'job_seekers.id', '=', 'ratings.js_id')
        ->groupBy('job_seekers.id')
        ->select('job_seekers.id', DB::raw('AVG( ratings.rating )  AS average_rating'))
        ->orderBy('average_rating', 'desc')
        ->get();

    return view('search.search_all', compact('jobseekers'));
}

在根据数据获得的评分进行搜索时如何排序数据，以及如何针对未评分的数据进行排序

1 个答案: