Question

我在angularjs中有3个作用域，一个来自一年，一个来自一个月，一个来自一天，来自3个输入框。我想将它们合并为日期，以下代码正确插入日期，但添加了22:00:00，如2019-06-01 22：00：00.000。如何只插入日期而没有时间

HTML

<div class="col-md-1">
    <div class="form-group has-error">
        <label class="title_lable">Year:</label>
        <input id="code" type="number" class="form-control input-sm"
               ng-model="year">
    </div>
</div>
<div class="col-md-2">
    <div class="form-group has-error">
        <label class="title_lable">Latin Description:</label>
        <input type="text" class="form-control input-sm"
               ng-model="latindesc">
    </div>
</div>
<div class="col-md-2">
    <div class="form-group">
        <label class="title_lable">Local Description:</label>
        <input type="text" class="form-control input-sm"
               ng-model="localdesc">
    </div>
</div>
<div class="col-md-1">
    <div class="form-group">
        <label class="title_lable">Month:</label>
        <select ng-show="lang==1" class="form-control input-sm"
                ng-model="month"
                ng-options="m.mnthid as m.mnthanm for m in months">
        </select>
        <select ng-show="lang==0" class="form-control input-sm"
                ng-model="month"
                ng-options="m.mnthid as m.mnthenm for m in months">
        </select>
    </div>
</div>
<div class="col-md-1">
    <div class="form-group">
        <label class="title_lable">Day:</label>
        <input type="number" class="form-control input-sm" ng-model="day">
    </div>
</div>

角度

var dFrom = new Date($scope.month + '/' + ($scope.day + 1) + '/' + $scope.year );
        var days = $scope.ndays;
        console.log(days);
        var todate = new Date($scope.month + '/' + ($scope.day +1) + '/' + $scope.year);
        todate = addDays(todate, days - 1);
        console.log(todate);

        var vacation = {
            Sys_Key: $scope.syskey,
            Vac_Code: $scope.code,
            L_Desc: $scope.latindesc,
            A_Desc: $scope.localdesc,
            V_Start_Date: $scope.day,
            V_Month: $scope.month,
            V_Days_Count: $scope.ndays,
            V_Year: $scope.year,
            From_Date: dFrom,
            To_Date: todate
        }

function addDays(startDate, numberOfDays) {
    var returnDate = new Date(
        startDate.getFullYear(),
        startDate.getMonth(),
        startDate.getDate() + numberOfDays,
        startDate.getHours(),
        startDate.getMinutes(),
        startDate.getSeconds()
    );
    return returnDate;
}

Answer 1

添加javascript时，请确保您使用的是数字值而不是字符串。您可以使用parseInt(string)

将字符串转换为整数

Answer 2

代码正确插入了日期，但添加了22:00:00，例如2019-06-01 22：00：00.000。如何只插入日期而没有时间

幕后日期被解析为UTC时间00:00小时。标准的.toString方法将其显示为本地时间。

var d = new Date("2019-06-01");

console.log(d.toString());

console.log(d.toISOString());

如果您希望将其解析为本地时间，请附加“ T00：00”

var d = new Date("2019-06-01T00:00");

console.log(d.toString());

console.log(d.toISOString());

如果没有时区偏移，则仅日期形式将被解释为UTC时间，而日期时间形式将被解释为本地时间。

有关更多信息，请参见

MDN JavaScript Reference - Date.parse()

Answer 3

您可以这样做

let dateString = "05/05/1997";

let date = new Date(dateString);

console.log(date.toLocaleString('en-US', {
      day:"2-digit",
      month:"2-digit",
      year:"numeric"
    }));

请通过以下链接签出

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/toLocaleString

收集数字并将它们转换为angularjs中的日期

3 个答案: