Question

我有一个值列表，基本上我想浏览一下该列表，并检查是否有20个以上的连续值低于某个最小值。如果是这样，我要结束列表中最后一个高于最小值的数字。

我尝试了以下失败的尝试：

def build_profile(first, last, **user_info):
         """Build a dictionary containing everything we know about a user."""
   profile = {}
   profile['first_name'] = first
   profile['last_name'] = last
   for key, value in user_info.items():
      profile[key] = value
   return profile
user_profile = build_profile('albert', 'einstein',
                  location='princeton',
                   field='physics')
print(user_profile)

Answer 1

您应该这样子- （将此视为伪代码）

your_list = [.....]
counter = 0
stop_at = 20  #Set it accordingly
minimum = 30  # Set it accordingly
split_at_index = None
for index, list_item in enumerate(your_list):
    if list_item < minimum:
        counter += 1
    else:
        counter = 0
        continue
    if counter == stop_at:
        split_at_index = index
        break
new_list = your_list[:split_at_index]

Answer 2

_list = [12,34,41,145,11,43,123,32]
counter = 0
limit = 3
thresold = 50
index = 0
split = 0
for num in _list:
    if num < thresold:
        counter = counter + 1
        print counter
        if counter == limit:
            split = index
            break
    else:
        counter = 0
    index = index + 1

print (_list[:split])

如果满足条件，如何截断列表

2 个答案: