Question

我正在尝试构建一个页面，该页面能够读取表格并将所选条目（时间，发件人，收件人，标题和内容）写下来，并且效果很好。

我面临的问题是第一个内容条目是这样的文本BLOB

ex.
TextTextTextTextTextText 
TextTextTextText
img1.jpg
TextTextTextTextText
TextTextTextTextTextText

img1.jpg保存在下一个BLOB内容条目中，必须经过base64编码才能作为图像打印，现在我被困在尝试将其写下来时

TextTextTextTextTextText
TextTextTextText
(actual image from the next entry)
TextTextTextTextText
TextTextTextTextTextText

我尝试用strpos检查内容是否包含下一个Blob的文件名，然后将其替换为实际图像，但是我无法设法在同一行中获取下一个表条目< / p>

这是正常输出的代码

$res = mysqli_query($link, createRequest(true, $link)) or die(mysqli_error($link));
while($row = mysqli_fetch_assoc($res)){

    $title = $row["a_subject"];
    $time = $row["create_time"];
    $sender = $row["a_from"];
    $reciever = $row["a_to"];
    $body = $row["content"];
    $articleid = $row["id"];

    if (strpos($body, '')){
        $img = "<pre>".'<img src="data:image/jpeg;base64,'.base64_encode( $body).'"/>'."</pre>"

    ?>
    <tr>
    <td><?php echo ($time) ?></td>
    <td><?php echo ($sender) ?></td>
    <td><?php echo ($reciever) ?></td>
    <td><?php echo ($title) ?></td>
    <td><?php echo $img ?></td>
    <td><a href=<?php echo "http://localhost/php/imageviewer.php?ArticleID=".$row["id"].""?>>Zeige Anhänge</a></td>
    </tr>
    <?php
    } else {
        ?>
    <tr>
    <td><?php echo ($time) ?></td>
    <td><?php echo ($sender) ?></td>
    <td><?php echo ($reciever) ?></td>
    <td><?php echo ($title) ?></td>
    <td><?php echo utf8_encode($body)?></td>
    <td><a href=<?php echo "http://localhost/php/imageviewer.php?ArticleID=".$row["id"].""?>>Zeige Anhänge</a></td>
    </tr>
    <?php

现在，我正在检查内容是图像还是只是一些文本，然后将其写下来。我想发生的事情是，可以说文本内容是：

text
img1
text
img2
text
img3

我当前的解决方案有4个html表项首先是

text
img1.jpg
text
img2.jpg
text
img3 .jpg

第二个是

actual image of img1.jpg

第三个存在

actual image of img2.jpg

等

我最后想要的是一个看起来像这样的表项

text
actual img1
text
actual img2
text
actual img3

Answer 1

好吧，据我所知，此表中有一些行是要显示的实际内容，包括对某些图像文件名的引用，然后在同一表中将这些实际图像存储为base64编码的BLOB。

我无法测试...，因此可以尝试一下，看看它是否提供您感兴趣的内容。

我评论了自己的添加内容，以使其更加清晰。

哦，我也使用了<?=的简写，纯粹是因为我认为它使代码更易于阅读/更易于使用。显然，如果您不想这样做，就不需要使用它！

<?php

<<PUT ANY OTHER EXISTING CODE HERE, E.G. THE START OF YOUR SCRIPT>>
$res = mysqli_query($link, createRequest(true, $link)) or die(mysqli_error($link));

// This function serves a dual purpose
// Given an image filename, e.g. `image001.png`, it will search the table for this filename and (hopefully) return a base64 encoded BLOB
// It then decodes this content and returns it
function get_image_from_filename ($filename, $db_connection) {
    $query = "SELECT article_attachment.content FROM article JOIN ticket ON article.ticket_id = ticket.id JOIN article_attachment on article.id = article_attachment.article_id WHERE article_attachment.filename = '$filename'";

    $res = mysqli_query($db_connection, $query) or die(mysqli_error($db_connection));

    while ($row = mysqli_fetch_assoc($res)) {
        return base64_decode($row["content"]);
    }
}

while($row = mysqli_fetch_assoc($res)) {

    $title = $row["a_subject"];
    $time = $row["create_time"];
    $sender = $row["a_from"];
    $reciever = $row["a_to"];
    $body = $row["content"];
    $articleid = $row["id"];

    if (base64_encode(base64_decode($body, true)) === $data){
        // If the `$body` can be decoded/encoded successfully, this row is an image - let's skip it
        continue;
    }
    else {
        // Otherwise, let's find all of the references to our images, and look them up in the database

        // This pattern will find the CID references and retrieve the associated image's filename
        $pattern = '/(?:cid:)([a-zA-Z0-9]+\.[a-zA-Z0-9]+)(@[a-zA-Z0-9]+\.[a-zA-Z0-9]+)+/';
        // This is the replacement that will be put into the `$body` variable, using the function at the top of this script
        $replacement = "<pre>" . '<img src="data:image/jpeg;base64,' . get_image_from_filename('$1', $link) . '" />' . "</pre>";

        $body = preg_replace($pattern, $replacement, $body);

?>

<tr>
    <td><?=$time?></td>
    <td><?=$sender?></td>
    <td><?=$receiver?></td>
    <td><?=$title?></td>
    <td><?=$body?></td>
    <td><a href="http://localhost/php/imageviewer.php?ArticleID=<?=$articleid?>">Zeige Anhänge</a></td>
</tr>

<?php

    } // End base64 if

}

如何用数据库表的下一个Blob条目替换Blob中的单词

1 个答案: