Question

这旨在检测用户在键入字母A后何时按下空格键。如果按下空格键，则应将A替换为C。否则，应将其单独放置。

此外，如果用户按空格键然后按退格键，则替换的字母（C）应该变为A，并且不再被替换。基本上是一个较弱的自动更正系统。

我的问题是，当我只是键入随机字母然后返回false时，报告是否按下空格键的布尔值会随机报告true。

对此将有任何新的关注！我似乎无法弄清楚是什么原因导致了这种情况的发生。预先感谢。

public class SpellingsClient extends Activity implements SpellCheckerSession.SpellCheckerSessionListener
{
TextWatcher tt = null;
private EditText suggestions;
@RequiresApi(api = Build.VERSION_CODES.JELLY_BEAN)
@Override
protected void onCreate (Bundle savedInstanceState){
    super.onCreate(savedInstanceState);
    suggestions = new EditText(this);
    setContentView(suggestions);
   // fetchSuggestionsFor(suggestions.getText().toString());

    tt = new TextWatcherExtended() {
        boolean movedOn;

        public void afterTextChanged(Editable s, boolean backSpace, boolean autoCorrect){
//Checks if the backspaced was pressed, sets movedOn to false if true
            suggestions.setSelection(s.length());
            if (backSpace){
                Log.d("test2", "Backspace pressed!" + backSpace);
                boolean movedOn = false;
            }
            Log.d("movedOn", "is " + movedOn);
            movedOn = true;
        } 

        public void beforeTextChanged(CharSequence s, int start, int count, int after){}

        public void onTextChanged(CharSequence s, int start, int before, int count){
//Checks if spacebar pressed and user moved on, then replaces the word
//if user pressed backspace, it sets the letters back to what they were
            suggestions.removeTextChangedListener(tt);
         if (spacePressed = true && movedOn) {
             suggestions.setText(suggestions.getText().toString().replace("A", "C"));
         } else if (!movedOn) {
             suggestions.setText(suggestions.getText().toString().replace("C", "A"));
         }
         suggestions.addTextChangedListener(tt);
        }
    };
    suggestions.addTextChangedListener(tt);
}
boolean spacePressed;

public boolean dispatchKeyEvent(KeyEvent event){
//checks if spacebar was pressed and sets spacePressed to true if so
    if (event.getKeyCode() == KeyEvent.KEYCODE_SPACE && event.getAction() == KeyEvent.ACTION_UP){
        Log.d("test", "Space bar pressed!" + event);
        spacePressed = true;
        return true;
    }
    Log.d("Spacepressed", "it's" + spacePressed);
    spacePressed = false;
    return super.dispatchKeyEvent(event);
}

Answer 1

spacePressed = true是您的问题。这是一项分配，而不是比较。

改为使用==；或者，更容易使用spacePressed，因为condition == true与condition相同，并且避免了可能出现错字的情况。

布尔值在应为假时报告为真

1 个答案: